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9966 [12]
3 years ago
14

PLZ HELP ITS DUE TODAY

Mathematics
1 answer:
Nady [450]3 years ago
8 0

9514 1404 393

Answer:

  x = {-0.44, 1.69}

Step-by-step explanation:

Multiply by the denominator to eliminate the fraction.

  3 = x(4x -5)

  4x^2 -5x -3 = 0 . . . . . subtract 3 and put in standard form

Using the quadratic formula with a=4, b=-5, c=-3, we have the solutions as ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-5)\pm\sqrt{(-5)^2-4(4)(-3)}}{2(4)}\\\\x=\dfrac{5\pm\sqrt{73}}{8}\approx \{-0.443, 1.693\}

Solutions rounded to hundredths are ...

  x = -0.44

  x = 1.69

_____

A graphing calculator can show the x-intercepts easily, so it works well to write the equation in the form

  f(x) = 0

  3/(4x -5) -x = 0

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Step-by-step explanation:

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An orange juice producer buys oranges from a large orange grove that has one variety of orange. The amount of juice squeezed fro
skad [1K]

Answer:

The probability is 70% that the sample mean amount of juice will be contained between 4.9168 ounces and 5.0832 ounces.

Step-by-step explanation:

To solve this question, the Normal probability distribution and the Central Limit Theorem are important.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 5, \sigma = 0.4, n = 25, s = \frac{0.4}{\sqrt{25}} = 0.08

The probability is 70% that the sample mean amount of juice will be contained between what two values symmetrically distributed around the population mean?

The lower end of this interval is the value of X when Z has a pvalue of 0.5 - 0.7/2 = 0.15

The upper end of this interval is the value of X when Z has a pvalue of 0.5 + 0.7/2 = 0.85

Lower end

X when Z has a pvalue of 0.15. So X when Z = -1.04.

Z = \frac{X - \mu}{\sigma}

Due to the Central Limit Theorem

Z = \frac{X - \mu}{s}

-1.04 = \frac{X - 5}{0.08}

X - 5 = -1.04*0.08

X = 4.9168

Upper end

X when Z has a pvalue of 0.15. So X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

Due to the Central Limit Theorem

Z = \frac{X - \mu}{s}

1.04 = \frac{X - 5}{0.08}

X - 5 = 1.04*0.08

X = 5.0832

The probability is 70% that the sample mean amount of juice will be contained between 4.9168 ounces and 5.0832 ounces.

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Answer:

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Step-by-step explanation:

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