What is 69.12 rounded to the nearest tenth

Ashley sells 18.6 kg bags of mixed nuts that contain 60% peanuts. To make her product she adds peanuts to Brand A's mixed nuts w

slavikrds [6]

Answer:

She combines 9.3 kg of each.

Step-by-step explanation:

Let x = amount of brand A in kg

Let y = amount of peanuts in kg

First we deal with the amount of each product she uses.

"Ashley sells 18.6 kg bags of mixed nuts that contain 60% peanuts."

x + y = 18.6

Now we deal with just the amount of peanuts.

"To make her product she adds peanuts to Brand A's mixed nuts which contain 20% peanuts."

Brand A contains 20% peanuts, so x kg of brand A contains 0.2x kg of peanuts.

The peanuts she adds are pure peanuts, so all of y is peanuts.

The result is 18.6 kg of a mixture that is 60% peanuts, so the amount of peanuts in the bags she sells is 0.6 * 18.6 kg.

0.2x + y = 0.6 * 18.6

0.2x + y = 11.16

We have a system of equations:

x + y = 18.6

0.2x + y = 11.16

We have y in both equations, so let's subtract the second equation from the first equation to eliminate y.

0.8x = 7.44

Divide both sides by 0.8

x = 9.3

Plug in 9.3 for x in the first equation of the system and solve for y.

x + y = 18.6

9.3 + y = 18.6

y = 9.3

Answer: She combines 9.3 kg of each.

4 0

2 years ago

(1, 1) and (4, 3) slope

Lostsunrise [7]

This needs to be 20 characters long but it’s 4/3

7 0

3 years ago

Read 2 more answers

Solve for x. 5/6 x = 10/3 x = 4/3 x = 2 x = 25/9 x = 4

SashulF [63]

Answer: LAST OPTION.

Step-by-step explanation:

In order to solve for the variable "x" from the expression $\frac{5}{6}x=\frac{10}{3}$ , you need to follow these steps:

1) You need to multiply both sides of the equation by 3:

$3(\frac{5}{6}x)=(\frac{10}{3})(3)\\\\\frac{15}{6}x=10$

2) You need to multiply both sides of the equation by 6:

$(6)(\frac{15}{6}x)=(10)(6)\\\\15x=60$

3) Finally, you can divide both sides of the equation by 15:

$\frac{15x}{15}=\frac{60}{15}\\\\x=4$

4 0

3 years ago

Read 2 more answers

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago

I need help ASAP on this algebra question

Misha Larkins [42]

Answer:

As x goes to negative infinity, g(x) goes to zero.

As x goes to positive infinity, g(x) goes to zero.

(So the answer is the second option)

Step-by-step explanation:

We have the function $g(x)=\frac{1}{x^2}$

First, let's look at what happens when we input smaller and smaller numbers

$g(-10)=\frac{1}{100} \\\\g(-100)=\frac{1}{10000}$

As we can see, as we input smaller and smaller numbers, the answer gets smaller.

Eventually, these fractions will be so small that they will get closer and closer to zero.

This same thing applies to larger and larger numbers, so the end behavior of each side will both be zero.

4 0

3 years ago