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Nutka1998 [239]
3 years ago
5

Using your knowledge of solving equations to solve the following problems. 7x-9y=1 y=-x+7

Mathematics
1 answer:
Arturiano [62]3 years ago
6 0

Answer:

-9y = -7x + 1

y = 7/9x -1/9 is the answer

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2 {x}^{3}  - 4 {x}^{2}  + 6x \\  = 2x( {x}^{2}  - 2x + 3) \\  \because \: 2x \: is \: common \: from \: all \: terms \\  \therefore \: greatest \: common \: factor = 2x

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Solve this please!! I'm really stuck
lora16 [44]

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-74.

Step-by-step explanation:

First, notice that we can divide it into 2 equations (1 on each side of the equal symbol).

<h3>1st step:</h3>

Replace where's x by -2 in the left equation:

x+\:-4+\:-2(3x-5)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:replace\:x\:by\:-2}\\-2+\:-4+\:-2((3\cdot-2)-5)=\square\mathrm{\:\:\:\:solve\:the\:multiplication}\\-2-4-2(-6-5)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:remove\:excess\:symbols}\\-2-4-2(-11)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:solve\:multiplication}\\-2-4+22=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:solve\:subtraction}\\16=\square

<h3>2nd step:</h3>

Now, we will replace the squares with 16 in the second equation. Look:

\square +-4+-2(3\cdot\square\cdot-5)=\triangle\\16 +-4+-2(3\cdot16-5)\\16-4-2(48-5)\\16-4-2(43)\\16-4-86\\=-74

So, the answer is -74.

<h2>We also can solve it in another way:</h2>

x-4-2(3x-5)=\\x-4-6x+10\\-5x+6\\\\\mathrm{let's\:replace\:x\:by\:-2:}\\-5\cdot(-2)+6\\10+6\\=16

Now let's call the gray square as y in the second equation:

y-4-2(3y-5)\\y-4-6y+10\\-5y+6\\\\\mathrm{let's\:replace\:y\:by\:16:}\\-5\cdot(16)+6\\-80+6\\=-74

So, your final answer is -74.

Hope it helps! :D

7 0
2 years ago
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