k = 18
the common difference d of an arithmetic sequence is
d = a₂ - a₁ = a₃ - a₂ = ....
a₂ - a₁ = 2k - 1 - k - 9 = k - 10 and
a₃ - a₂ = 2k + 7 - (2k - 1) = 2k + 7 - 2k + 1 = 8, hence
k - 10 = 8 ⇒ k = 8 + 10 = 18
the 3 consecutive terms are
27, 35, 43
X=46.2
_____________________________
99.2 + 62 = 161.2
180 -161.2 = 19.8
19.8 + 112 = 131.8
180 - 131.8 = 48.2
48.2 - 2 = 46.2
6.3 = 0.9y
y would equal 7
Answer:
11 4-passenger cars
Step-by-step explanation:
let 'x' represent the number of 4-passenger cars,then 'x-3' represent the number of 6-passenger cars.
92=4x+6(x-3)
92=4x+6x-18
92=10x-18
92+18=10x
110=10x
x=110/10
x=11
Therefore there are 11 4-passenger cars
