Answer:
advanced education
Explanation:
just got it right on edge 2020
Answer:
Explanation:
Postage expense. 1320
freight out. 1140
miscellaneous exp. 150
Cash. 2610
to replenish petty cash account
note that pettty cash is only debited or credited when you are increasing Or decreasing the petty cash fund. This entry appears to be only replenishing the petty cash account.
Answer:
The answer would be neutrality of money theory
Explanation:
The neutrality of money theory claims that changes in the money supply affect the prices of goods, services, and wages but not overall economic productivity. Many of today's economists believe the theory is still applicable, at least over the long run.
Answer:
The answer is A
Explanation:
Competitive environment is an environment where competitors compete with one another for customers.
For example, Westpac, NAB, Commonwealth Bank and ANZ are in the same competitive environment. These are banks in Australia.
Types of competition are perfect competition, monopoly, monopolistic competition, oligopoly etc.
Answer:
- <em>As explained below, given that the score of the person is among the 0.03125 fraction of the best applicants, </em><u><em>he can count on getting one of the jobs.</em></u>
<em></em>
Explanation:
The hint is to use <em>Chebyshev’s Theorem.</em>
Chebyshev’s Theorem applies to any data set, even if it is not bell-shaped.
Chebyshev’s Theorem states that at least 1−1/k² of the data lie within k standard deviations of the mean.
For this sample you have:
- mean: 60
- standard deviation: 6
- score: 84
The number of standard deviations that 84 is from the mean is:
- k = (score - mean) / standar deviation
- k = (84 - 60) / 6 = 24 / 6 = 4
Thus, the score of the person is 4 standard deviations above the mean.
How good is that?
Chebyshev’s Theorem states that at least 1−1/k² of the data lie within k standard deviations of the mean. For k = 4, that is:
- 1 - 1/4² = 1 - 1/16 = 0.9375
- That means that half of 1 - 0.9375 are above k = 4: 0.03125
- Then, 1 - 0.03125 are below k = 4: 0.96875
Since there are 70 positions and 1,000 aplicants, 70/1,000 = 0.07. The compnay should select the best 0.07 of the applicants.
Given that the score of the person is among the 0.03125 upper fraction of the applicants, this person can count of geting one of the jobs.