<span><span>If you would like to know what is 12/15 in the simplest form, you can calculate this using the following
step:</span><span>
12/15<span> simplifies to 4/5 (the common factor of 12 and 15 is 3, so you can divide both numbers by 3).</span>
<span>The result is 4/5.</span></span></span>
Probability that both roads from a to b are blocked is the product of the individual probabilities, i.e.
P(~ab)=0.25*0.25=0.0625
Similarly
P(~bc)=0.25*0.25=0.0625
Probability that EITHER one or both of ab and bc are blocked is the sum of the probabilities:
P(~ab ∪ ~bc)=0.0625+0.0625=0.125
(recall that one cannot travel from a to c if either ab or bc is blocked.)
Therefore the probability that there exists an open route from a to c
= P(ac) = 1-P(~ab ∪ ~bc)
= 1 - 0.125
=0.875
Answer: feet: 1, 2, 3, 4, 5
inches: 12, 24, 36, 48, 60
Step-by-step explanation:
There are 12 inches in a foot, therefore if you have 1 foot you have 12 inches, if you have 2 feet you have 24 inches becauase 2*12 = 24 and so on...
Answer:
15 cups
Step-by-step explanation:
The formula to find cups from quarts C = Q * 4, where c is how many cups, and Q how many quarts. To find how many cups are in a quart, simply multiply the number of quarts by 5. In this case, there are 3 3/4 quarts of coffee, multiply that by 5, and you would get 15 cups of coffee!
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
