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Whitepunk [10]
2 years ago
15

X + 2x + 12y + 4 I don't know the answer can someone help me please

Mathematics
2 answers:
kolbaska11 [484]2 years ago
6 0

Answer:

The asnwer is 3x + 12y + 4

sergey [27]2 years ago
4 0

Answer:

I think you wrote it wrong but if not here

Step-by-step explanation:

Simplifying

2x + -12y = 4

Solving

2x + -12y = 4

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12y' to each side of the equation.

2x + -12y + 12y = 4 + 12y

Combine like terms: -12y + 12y = 0

2x + 0 = 4 + 12y

2x = 4 + 12y

Divide each side by '2'.

x = 2 + 6y

Simplifying

x = 2 + 6y

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Step-by-step explanation:

8y^2 + 3xy + 2y^2 - 4xy

8y^2 + 2y^2 + 3xy - 4xy

10y^4 - 1xy

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Solve <img src="https://tex.z-dn.net/?f=2%20cosx%3D4cosx%20sin%5E2x" id="TexFormula1" title="2 cosx=4cosx sin^2x" alt="2 cosx=4c
Ilia_Sergeevich [38]

There are four solutions for the <em>trigonometric</em> equation 2 · cos x = 4 · cos x · sin² x are x₁ = π/4 ± 2π · i, x₂ = 3π/4 ± 2π · i, x₃ = 5π/4 ± 2π · i and x₄ = 7π/4 ± 2π · i, i \in \mathbb{N}_{O}.

<h3>How to solve a trigonometric equation</h3>

In this problem we must simplify the <em>trigonometric</em> equation by both <em>algebraic</em> and <em>trigonometric</em> means and clear the variable x:

2 · cos x = 4 · cos x · sin² x

2 · sin² x = 1

sin² x = 1/2

sin x = ± √2 /2

There are several solutions:

x₁ = π/4 ± 2π · i, i \in \mathbb{N}_{O}

x₂ = 3π/4 ± 2π · i, i \in \mathbb{N}_{O}

x₃ = 5π/4 ± 2π · i, i \in \mathbb{N}_{O}

x₄ = 7π/4 ± 2π · i, i \in \mathbb{N}_{O}

There are four solutions for the <em>trigonometric</em> equation 2 · cos x = 4 · cos x · sin² x are x₁ = π/4 ± 2π · i, x₂ = 3π/4 ± 2π · i, x₃ = 5π/4 ± 2π · i and x₄ = 7π/4 ± 2π · i, i \in \mathbb{N}_{O}.

To learn more on trigonometric equations: brainly.com/question/27821667

#SPJ1

4 0
2 years ago
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