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VashaNatasha [74]
2 years ago
12

Type the missing number in this sequence

Mathematics
2 answers:
svlad2 [7]2 years ago
8 0

Answer:

101

Step-by-step explanation:

please mark me as brainliest

konstantin123 [22]2 years ago
7 0

Answer:

amog us

Step-by-step explanation:

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5) In the figure, triangle ABC is a right triangle at B. If CD = 15, find BC to the nearest tenth.
ycow [4]

Answer:

BC ≈ 4.0

Step-by-step explanation:

∠ DCA = 180° - 70° = 110° ( adjacent angles )

∠ DAC = 180° - (30 + 110)° ← sum of angles in triangle

∠ DAC = 180° - 140° = 40°

Using the Sine rule in Δ ACD to find common side AC

\frac{AC}{sin30} = \frac{15}{sin40} ( cross- multiply )

AC × sin40° = 15 × sin30° ( divide both sides by sin40° )

AC = \frac{15sin30}{sin40} ≈ 11.668

Using the cosine ratio in right triangle ABC

cos70° = \frac{adjacent}{hypotenuse} = \frac{BC}{AC} = \frac{BC}{11.668} ( multiply both sides by 11.668 )

11.668 × cos70° = BC , then

BC ≈ 4.0 ( to the nearest tenth )

6 0
3 years ago
Devin wants to use his 12% employee discount to buy a video game that is priced at $57.80. A 8.75% sales tax is applied to the d
lesantik [10]

Answer:

43.73

Step-by-step explanation:

use a calculater

5 0
3 years ago
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Does anyone know this?
PIT_PIT [208]

Answer:

it has 5

Step-by-step explanation:

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3 years ago
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Someone answer this please
lions [1.4K]

Answer:

1,334.5 \:  {cm}^{3}

Step-by-step explanation:

Height of the cylinder h = 17 cm

Radius of the cylinder r = 5 cm

V_{cylinder}  = \pi {r}^{2} h \\  \\  = 3.14 \times  {(5)}^{2}  \times 17 \\  \\  = 3.14 \times 25 \times 17 \\  \\V_{cylinder}  = 1,334.5 \:  {cm}^{3}

7 0
3 years ago
given a geomatric progression 2,6,18,54... find the smallest value of n such that the nth term is greater than 100000​
stiks02 [169]

Answer:

hello,

Step-by-step explanation:

u_1=2=2*3^0\\u_2=6=2*3^1\\u_3=18=2*3^2\\u_4=54=2*3^3\\\\....\\u_n=2*3^{n-1}\geq 100000\\\\3^{n-1}\geq 50000\\\\(n-1)*ln(3)\geq ln(50000)\\\\n-1\geq 9,848586...\\\\n\geq 10.848586....\\\\\boxed{n=11}\\

6 0
2 years ago
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