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NeX [460]
3 years ago
13

Solve. 7 pounds x 16 ounces = pounds plz hero

Mathematics
1 answer:
Rama09 [41]3 years ago
4 0
The answer is 7 pounds because 16 ounces is equal to 1 pound so 7 pounds times 1 pound would equal 7 pounds.
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10% of a group is left handed. If a random sample of 12 switches is selected, what is the probability of exactly two of the swit
Paraphin [41]
Assuming that 10% is the probability of a switch being defective (since left-handedness has nothing to do with the problem):
For a binomial distribution, probability(r out of n) = (nCr) (p)^r (q)^(1-r)
p = 10% = 0.1, q = 1 - p = 0.9
r = 2 switches, n = total of 12 switches
probability = (12C2) (0.1)^2 (0.9)^(12-2)
probability = 66(0.1)^2 (0.9)^10
probability = 0.23
4 0
3 years ago
18.24 + 22.09 =<br> Plz show work
natulia [17]

Answer:

40.33

Step-by-step explanation:

First, add 18 and 22(you get 40. Then, add the decimals (you get .33). After that, put them together.

3 0
3 years ago
NEED HELP PLEASEE
Kruka [31]

Answer:

Simplify−412+16t+48.h=16t−1633

Step-by-step explanation:

4 0
4 years ago
Based upon a smaller sample of only 170 st. paulites, what is the probability that the sample proportion will be within of the p
Pepsi [2]
Given that in 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hired by the Better Business Bureau to investigate the complaints they received this year involving new car dealers. You plan to select a sample of new car dealer complaints to estimate the proportion of complaints the Better Business Bureau is able to settle. Assume the population proportion of complaints settled for new car dealers is .75, the same as the overall proportion of complaints settled in 2008.


Part a) :

Suppose you select a sample of 450 complaints involving new car dealers. Show the sampling distribution of (to 4 decimals).

Population proportion = 0.75
sample size. n = 450
Standard\ error=\sqrt{\frac{p(1-p)}{n}}  \\  \\ =\sqrt{\frac{(0.75)(0.25)}{450}} = 0.0204

Therefore, the sampling distribution has a proportion of 0.75 and a standard error of 0.0204.



Part b) :

Based upon a sample of 450 complaints, what is the probability that the sample <span>proportion will be within .04 of the population proportion (to 4 decimals)?

The probability </span><span>that the sample proportion will be within 0.04 of the population proportion</span> is given by:

P(p\ \textless \ 0.75\pm0.04)=2P\left(z\ \textless \  \frac{0.04}{0.0204} \right)-1 \\  \\ 2P(z\ \textless \ 1.961)-1=2(0.97505)-1=1.9501-1 \\  \\ =\bold{0.9501}

Therefore, the probability that the sample <span>proportion will be within .04 of the population proportion is 0.9501.



Part C:

</span><span>Suppose you select a sample of 200 complaints involving new car dealers. Show the sampling distribution of (to 4 decimals).

</span><span>Population proportion = 0.75
sample size. n = 200
Standard\ error=\sqrt{\frac{p(1-p)}{n}}  \\  \\ =\sqrt{\frac{(0.75)(0.25)}{200}} = 0.0306

Therefore, the sampling distribution has a proportion of 0.75 and a standard error of 0.0306.



Part D):

Based upon the smaller sample of only 200 complaints, what is the probability that the sample proportion will be within .04 of the population proportion (to 4 decimals)?

</span><span><span>
The probability </span>that the sample proportion will be within 0.04 of the population proportion is given by:

P(p\&#10; \textless \ 0.75\pm0.04)=2P\left(z\ \textless \  \frac{0.04}{0.0306} &#10;\right)-1 \\  \\ 2P(z\ \textless \ 1.306)-1=2(0.90429)-1=1.80858-1 \\  \\&#10; =\bold{0.8086}

Therefore, the probability that the sample <span>proportion will be within .04 of the population proportion is 0.8086.</span></span>
8 0
3 years ago
Pls someone help me find the answers
Alecsey [184]

Answer:

x = 145°

Step-by-step explanation:

We know that y = 98°, so we can find ∠DBC:

180°-y = ∠DBC

180°-98° = 82°

We also know that z = 63°, therefore we can apply <u>exterior angle of triangles</u> to find x.

∠DBC + z = x

82°+63° = x

x = 145°

7 0
3 years ago
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