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3 years ago

In a box of 150 paper clips, 81 are red. Which equation represents the

Mathematics

2 answers:

Vilka [71]3 years ago

8 0

Answer:

Step-by-step explanation:

X=150×81/100

X=12,150/100

X=121.5.

Colt1911 [192]3 years ago

4 0

The ratio is 81:150 or in simplistic terms 27:50. This means that for every 50 marbles, 27 of them is red.

To find percentage, place the amount of red marbles over the amount of marbles and multiply by 100.

81/150 x 100 = 54%

Or

27/50 x 100 = 54%

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You plan to go to a technical school, and there are two options in your city. School A will charge you $750 per semester for tui

d1i1m1o1n [39]

Lets set an equation for each option. 1) School A: Charge = 750 + 200 = 950 per monts. 2) School B: 1000 less 10% discount from you employer. = 1000 - 1000*0.10 = 1000 - 100 = 900. Then, youcan save money going to School B, thanks to the discount that you will receive through your employer.

5 0

3 years ago

Nico, Aditi, Erick, Raj, and Sandra are solving the equation.

Alex777 [14]

Answer:

Nico, Raj and Sandra are correct

Step-by-step explanation:

we have

$\frac{2}{5}(5+x)=8$

Method 1

Solve for x

That means ----> isolate the variable x

we have

$\frac{2}{5}(5+x)=8$

Multiply by 5/2 both sides

$(\frac{5}{2})\frac{2}{5}(5+x)=(\frac{5}{2})8$

$5+x=20$

subtract 6 both sides

$5+x-5=20-5$

$x=15$

Method 2

Solve for x

That means ----> isolate the variable x

we have

$\frac{2}{5}(5+x)=8$

Multiply by 1/2 both sides

$(\frac{1}{2})\frac{2}{5}(5+x)=(\frac{1}{2})8$

$\frac{1}{5}(5+x)=4$

Multiply by 5 both sides

$(5)\frac{1}{5}(5+x)=(5)4$

$5+x=20$

subtract 6 both sides

$5+x-5=20-5$

$x=15$

Method 3

Solve for x

That means ----> isolate the variable x

we have

$\frac{2}{5}(5+x)=8$

Apply distributive property left side

$\frac{2}{5}(5)+\frac{2}{5}(x)=8$

$2+\frac{2}{5}(x)=8$

subtract 2 both sides

$2+\frac{2}{5}(x)-2=8-2$

$\frac{2}{5}(x)=6$

Multiply by 5/2 both sides

$(\frac{5}{2})\frac{2}{5}(x)=(\frac{5}{2})6$

$x=15$

therefore

Nico, Raj and Sandra are correct

6 0

4 years ago

Read 2 more answers

The center of a hyperbola is (-5,8). The length of the conjugate axis is 6 units, and the length of the transverse axis is 14 un

serious [3.7K]

Answer:

$(\frac{x+5}{3}) ^{2}+ (\frac{y-8}{7} )^{2} =1$

Step-by-step explanation:

IMPORTANT FORMULA: the standard equation of a hyperbola whose transverse axis is parallel to the y axis is:

$(\frac{x-h}{a}) ^{2}+ (\frac{y-k}{b} )^{2} =1$

where, (h,k) : center of the hyperbola

a : semi conjugate axis [ length of conjugate axis/2]

b: semi transverse axis [ length of transverse axis/2]

so, here a=3, b=7, [h,k]=[-5,8]

by substituting these values in the above given formula,

the equation of the hyperbola in standard form is :

$(\frac{x-(-5)}{3}) ^{2}+ (\frac{y-8}{7} )^{2} =1$

$(\frac{x+5}{3}) ^{2}+ (\frac{y-8}{7} )^{2} =1$

8 0

4 years ago

Here is another for fun question. MUST SHOW ALL WORKINGS

romanna [79]

For the product of the digits to be divisible by 10, it must have 10 as a factor, of course. Since 10 can't act as a digit, this means two of our digits must be 2 & 5.

No digit can be 0 because this would give a total product of 0.

Neither 2 nor 5 can be our largest because the lowest you can get is 1+2+3=6.
The lowest possible largest digit would have to be 1+2+5=8.
As for 9, this is not an option, and here's why: We need that 2 and 5, but to get 9 our other digit would have to be 2, which is a repeat.

So, our digits are 1, 2, 5, and 8.
It doesn't matter which order they are in. (take a look at the rules)
Therefore, we should put the highest digits in the highest value places.

The answer is $\boxed{8521}$

3 0

4 years ago

What is the slope of the line below? If necessary, enter your answer as a

Elanso [62]

Answer:

Step-by-step explanation:

(-4 - 6)/(1 - 6) = -10/-5 = 2

8 0

3 years ago

Read 2 more answers