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Anon25 [30]
3 years ago
13

Mellisa created a graph

Mathematics
1 answer:
vovikov84 [41]3 years ago
6 0

Answer:

no she didn't

Step-by-step explanation:

melissa has no hands

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Item 16 Evaluate 2x+6y when x=?45 and y=13. Write your answer as a fraction
Marrrta [24]

Answer:

168

Step-by-step explanation:

2x45=90

6x13=78

78+90=168

4 0
4 years ago
Fraction 12-20 conversed into a decimail
rjkz [21]
0.6

I think this will help you
5 0
4 years ago
Work out <br> -11x = 220<br> x= ?
irina1246 [14]

Answer:

<h2>-20</h2>

Step-by-step explanation:

divide both by -11 ->

x  = - 20

3 0
4 years ago
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What is the answer to this equation 1/3÷4/5
Damm [24]

Answer:

5/12

Step-by-step explanation:

to divide fractions you find the reciprocal of the 2nd number

and times both of the numbers

1/3 times 5/4

Multiply numerator and denominator.

=5/12

3 0
3 years ago
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What is the inverse of this function? (Function in photo)
valkas [14]

Given:

The function is

f(x)=-\dfrac{1}{2}\sqrt{x+3},x\geq -3

To find:

The inverse of the given function.

Solution:

We have,

f(x)=-\dfrac{1}{2}\sqrt{x+3}

Put f(x)=y.

y=-\dfrac{1}{2}\sqrt{x+3}

Interchange x and y.

x=-\dfrac{1}{2}\sqrt{y+3}

Isolate the variable y.

-2x=\sqrt{y+3}

(-2x)^2=y+3

4x^2-3=y

y=4x^2-3

Putting y=f^{-1}(x), we get

f^{-1}(x)=4x^2-3

For x\geq -3,

x+3\geq 0

\sqrt{x+3}\geq 0

-\dfrac{1}{2}\sqrt{x+3}\leq 0

f(x)\leq 0

It means for function f(x)\leq 0 and for inverse function x\leq 0 because the range of the function is the domain of inverse function.

Therefore, f^{-1}(x)=4x^2-3 for x\leq 0.

3 0
3 years ago
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