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Ahat [919]
3 years ago
9

Algebra 2 Logarithms Problem!!! Pls explain how you did the work for all parts-- i will give brainliest!!!!!

Mathematics
1 answer:
monitta3 years ago
5 0

Answer:

<u>Given</u>

  • log₃ 20 = x and log₃ 2 = y

<u>Properties used</u>

  • <em>log ab = log a  + log b</em>
  • <em>log a/b = log a - log b</em>
  • <em>log aᵇ = b log a</em>

a)

  • log₃ 400 = log₃ (20)² = 2 log₃ 20 = 2x

b)

  • log₃ 80 = log₃ (20*4) = log₃ 20 + log₃ 4 = log₃ 20 + 2log₃ 2 = x + 2y

c)

  • log₃ 40 = log₃ (20*2) = log₃ 20 + log₃ 2 = x + y

d)

  • log₃ 10 = log₃ (20/2) = log₃ 20 - log₃ 2 = x - y
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Answer:

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Step-by-step explanation:

-2+7(x+8)

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ASAP 6(a + 25 + 3c) =
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Answer:

6a+150+18c

Step-by-step explanation:

6(a+25+3c)

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(7^2)^6=7^2 X^6<br><br> Value of x
borishaifa [10]

X±49

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3 years ago
Identify the pairs of congruent angles and proportional sides in the following figures.
Vinvika [58]

Answer:

Step-by-step explanation:

congruent angles:

angle A = H

B = J

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AB proportional HJ

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hope it helps

if it does so then please mark me as brainliest

7 0
3 years ago
Find the angle measure indicated to the nearest tenth:
makvit [3.9K]

Step-by-step explanation:

Sin<D = Opposite / Hypotenuse

Opposite - EC

Hyp - DE

Sin<D = EC/DE = x/9

we need x to find <D.

so -->Use pythagorean theorem.

DE^2 = EC^2 + DC^2

DE = 9 DC = 7 EC = ?

EC^2 = DE^2 - DC^2 rearranged.

= 9^2 - 7^2

= 81 - 49

EC^2 = 32 Put both sides under square root.

√(EC^2) = √32

EC = 4√2 ~ 5.65.

We now have X which was representing the unknown side EC.

Sin<D = EC/DE = 5.65/9 = 0.627

To find <D Take the sine inverse of of 0.627.

<D = Arcsin(0.627) = 38.82°.

We now know <D. It's <E's turn.

A right angle triangle has a summation of interior angles of 180°.

thus, <em><D + <C + <E = 180°</em>

38.82° + 90° + <E = 180°

128.82° + <E = 180°

subtract both sides by 128.82°

0 + <E = 180° - 128.82°

<em><E = 51.</em><em>2</em><em>°</em>

6 0
2 years ago
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