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3 years ago

Tell whether x and y show direct variation. Explain your reasoning. If so, find k. y+3=x+6

Mathematics

1 answer:

strojnjashka [21]3 years ago

6 0

Answer:

No, they don't.

Step-by-step explanation:

The point (0, 0) is not a solution to the equation, so the relationship cannot be direct variation.

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A weighted coin has a 0.599 probability of landing on heads. What is the probability that it takes 5 flips for the first head to

natka813 [3]

Answer:

0.411^5 times 0.599

Step-by-step explanation:

0.599 chance of landing on heads.

0.411 chance of not landing on heads.

0.411 times 0.411 times 0.411 times 0.411 times 0.411 (for the 5 flips that do not land on heads) times 0.599 (for the time that it does land on heads).

6 0

3 years ago

Find the inverse of ????−7 −2

Masja [62]

Answer:

$A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

Step-by-step explanation:

$A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}$

$det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1$

$A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}$

Hence, confirmed

6 0

4 years ago

I am in pre-algebra and i need help answering a question for homework..

Elenna [48]

the answer is x is equal to -4

x=-4

3 0

3 years ago

Read 2 more answers

Find the sum of the following geometric sequences. d) 3 terms a= 16 r=3/4

kodGreya [7K]

Answer:

S₃ = 37

Step-by-step explanation:

given a₁ = 16 and r = $\frac{3}{4}$ , then

a₂ = a₁ × $\frac{3}{4}$ = 16 × $\frac{3}{4}$ = 12

a₃ = a₂ × $\frac{3}{4}$ = 12 × $\frac{3}{4}$ = 9

then

S₃ = a₁ + a₂ + a₃ = 16 + 12 + 9 = 37

7 0

2 years ago

Both questions 7 and 8

Anna35 [415]

9514 1404 393

Answer:

7. $10,459.28

8. $30,060.93

Step-by-step explanation:

Your table 12-2 will tell you the present-value multiplier of the annual payment for a 10-year annuity due will be ...

7%: 7.515232

11%: 6.537048

7. The 11% table value will be used with a payment of $1600 to find the present value:

6.537048 × $1600 = $10,459.28 . . . present value of the annuity due

8. The 7% table value will be used with a payment of $4000 to find the present value:

7.515232 × $4000 = $30,060.93 . . . present value of the annuity due

6 0

2 years ago