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MAVERICK [17]
3 years ago
5

The last one under m<1+m<3 is m<5+M<6

Mathematics
1 answer:
ElenaW [278]3 years ago
8 0

Answer:

the first answer choice

Step-by-step explanation:

have a great day :D

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I need help with this one question<br> 8r - 5q = 3<br> solve for q <br> how do i go about this
KATRIN_1 [288]
8r - 3 = 5q --> q = (8r - 3)/5
6 0
3 years ago
How many, and what type of, solutions does 4x² + 12x + 9 = 0 have? 2 irrational solutions 1 rational solution 2 nonreal solution
SVEN [57.7K]

The discriminant is

\sqrt{ {12}^{2}  - 4(4)(9)}

which is 0.

Since the discriminant is 0, there is only one real solution.

4 0
3 years ago
Can someone help me with these and show the work also?
Snezhnost [94]

QUESTION:

Simplify each expression

ANSWER:

1.) \green{{- 8n}}

2.) \green{{- 2b - 60}}

3.) \green{{- 10x - 14}}

4.) for number 4 study my step-by-step explanation so you can answer that

STEP-BY-STEP EXPLANATION:

1.) First, If the term doesn't have a coefficients, it is considered that the coefficients is 1

WHY?

Learn why:

Why is it considered that the coefficient is 1?

Remember that any term multiplied by \blue{{1}} remains the same :

\blue{{1}} {× x = x}

Step 1:

The equality can be read in the other way as a well, so any term can be written as a product of \blue{{1}} and itself:

{x = } \blue{{1}} {× x}

Step 2:

Usually, we don't need to write multiplacation sign between the coefficient and variable, so the simple form is:

{x = 1x}

This is why we can write the term without the coefficient as a term with coefficient {1}

Now let's go back to solving as what i said if a term doesn't have a coefficient, it is considered that the coefficient is 1

{n - 9n}

\red{{1}} {n -9n}

Second, Collect like terms by subtracting their coefficients

\red{{1n - 9n}}

\red{{( 1 - 9)n}}

Third, Calculate the difference

how?

Keep the sign of the number with the larger absolute value and subtract the smaller absolute value from larger

\red{{1 - 9}}

\red{{- (9 - 1)}}

Subtract the numbers

- (\red{{9 - 1}})n

- \red{{8}}n

\green{\boxed{- 8n}}

2.) First, Distribute - 6 through the parentheses

how?

Multiply each term in the parentheses by - 6

\red{{- 6(b + 10)}}

\red{{- 6b - 6 × 10}}

Multiply the numbers

- {6b} - \red{{6 × 10}}

- {6b} - \red{{60}}

Second, Collect like term

how?

Collect like terms by calculating the sum or difference of their coefficient

\red{{- 6b + 4b}}

\red{{(- 6 + 4)b}}

Calculate the sum

\red{{(- 6 + 4)}}b

\red{{-2}}b

\green{\boxed{- 2b - 60}}

3.) First, Distribute 2 through parentheses

how?

Multiply each term in the parentheses by 2

\red{{2(x - 5)}}

\red{{2x - 2 × 5}}

Multiply the numbers

{2x -} \red{{2 × 5}}

{2x -} \red{{10}}

Second, Distribute - 4 through the parentheses

how?

Multiply each term in the parentheses by - 4

\red{{- 4(3x + 1)}}

\red{{- 4 × 3x - 4}}

Calculate the product

- \red{{4 × 3}}x - 4

- \red{{12}}x - 4

Third, Collect like terms

how?

Collect like terms by subtracting their coefficient

\red{{2x - 12x}}

\red{{(2 - 12)x}}

Calculate the difference

\red{{(2 - 12)}}x

\red{{- 10}}x

Fourth, Calculate the difference

how?

Factor out the negative sign from the expression

\red{{- 10 - 4}}

\red{{- (10 + 4)}}

Add the numbers

- (\red{{10 + 4}})

- \red{{14}}

\green{\boxed{- 10x - 14}}

That's all I know sorry but I hope it helps :)

6 0
2 years ago
Find the length of the unknown side. Round your answer to the nearest tenth. (4 points) Image of a right triangle with a leg lab
Anika [276]

using pythagorean theorem

a^2 + b^2 =c^2

a^2 +8^2 =14^2

a^2 +64 = 196

subtract 64 from each side

a^2 = 132

take the square root of each side

a^2 = sqrt (132)

a=11.48912529

a =11.5

5 0
3 years ago
In Buffalo, New York the temperature was -14 degrees in the morning. if the temperature dropped 7 degrees. what is the degrees n
Veseljchak [2.6K]

Answer:

-21

Step-by-step explanation:

-14 - 7 = -21

4 0
3 years ago
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