The length and the width of the rectangle are 20 and 14 inches respectively
<h3>How to find the length and width?</h3>
The given parameters are:
Length = 6 + Width
Perimeter = 68 inches
The perimeter of a rectangle is calculated as:
Perimeter = 2 * (Length + Width)
So, we have:
2 * (Length + Width) = 68
Divide both sides by 2
Length + Width = 34
Substitute Length = 6 + Width in Length + Width = 34
6 + Width + Width = 34
Evaluate the like terms
2 * Width = 28
Divide both sides by 2
Width = 14
Substitute Width = 14 in Length = 6 + Width
Length = 6 + 14
Evaluate
Length = 20
Hence, the length and the width of the rectangle are 20 and 14 inches respectively
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Sorry for the delay but I answered your question and the answer is -6xsquare +11x-4
Answer:
-2
Step-by-step explanation:
x^2 + x=2
Subtract 2 from each side
x^2 + x-2=2-2
x^2 + x-2=0
Factor
What 2 numbers multiply to -2 and add to 1
2*-1 = -2
2+-1 =1
(x-1)(x+2)=0
Using the zero product property
x-1 = 0 x+2 = 0
x=1 x = -2
Product of the roots
1*-2 = -2
Answer:
220
Step-by-step explanation:
110 cannot be the lcm for 20 but 10 and 110
so 220 can be the lcm for 20, 10, and 110
hope this helps
