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Mrrafil [7]
3 years ago
14

Write an exponential function for the graph that passes through the points (0,4) and (2, 36). Use the formula y=ab^x​

Mathematics
1 answer:
fomenos3 years ago
3 0

Answer:

Using the equation y = abx , substitute both of your given points into that equation.

2 = ab2 and 4 = ab3   Solve each equation for a.

2⁄b2    and 4⁄b3 = a     Therefore, 2⁄b2 = 4⁄b3

                                   

Cross multiply: 2b3 = 4b2     Divide both sides by b2

2b = 4      a = 2/4 = 1/2

b = 2

y = 1 (2)x

     2

Step-by-step explanation:

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A circular tablecloth has a diameter of 70 inches. Max wants to add a decorative fabric around the edge of the tablecloth.Approx
JulijaS [17]

Answer:

219.8

Step-by-step explanation:

you multiply 70 and 3.14 and get 219.8

5 0
2 years ago
What is the value of x in the equation <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7Dx%20-%5Cfrac%7B2%7D%7B3%7D" id="Te
SVEN [57.7K]

Answer:

x= 200

Step-by-step explanation:

The given equation is:

1/5 x - 2/3 y = 30

The value of y is 15

Put the value of y in the given equation:

1/5 x - 2/3(15) = 30

1/5 x- 10 = 30

Take the L.C.M of the denominator

x-50/5 = 30

Move the denominator to the R.H.S

x-50 = 30*5

x-50 = 150

Combine the like terms

x= 150+50

x = 200

The value of x is 200...

5 0
3 years ago
Read 2 more answers
Please help! ill mark you as brain if your right!!!!
yulyashka [42]

Answer:

SA = 1099 square inches.

Step-by-step explanation:

Just plug into the formula

SA = 2pir^2 + 2pi r h where pi = 3.14, r = 5 and h = 30

SA = 2 (3.14) (5^2) + 2 (3.14)(5)(30)

SA = 157 + 942

SA = 1099 square inches.

6 0
3 years ago
Read 2 more answers
Find g(x), where g(x) is the reflection across the x-axis of f(x)=<br> –<br> 4(x–10)2+3.
Dahasolnce [82]
8x-77 would be the answer to this
3 0
2 years ago
Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)

J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)

K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)

L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)

M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)


5 0
3 years ago
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