<h2>Length = 11</h2><h2>Width = 6</h2>
The area of a rectangle is 66 ft^2:
L * W = 66
Length of the rectangle is 7 feet less than three times the width:
L = 3W-7
Substitute L in terms of W:
(3W-7) * W = 66
Factorise the equation:
3W^2 -7W = 66
3W^2 - 7W - 66 = 0
Factors of 66 =
1 66, 2 33, 3 22, 6 11
(3W + 11) (W - 6) = 0
Solve for W:
3W + 11 = 0
3W = 11
W = 3/11
W - 6 = 0
W = 0 + 6
W = 6
Using the original equation, find L:
L = 3W-7
L = 3(6)-7
L = 18-7
L = 11
L * W = 66
11 * 6 = 66
Total kicks that were attempted = 40
Goals blocked by Kyra = 55%;
Goals which could not be blocked by Kyra = 100 - 55 = 45%
Goals made during team drill = 18
Let total kicks attempted be 'n';
Therefore;
(18/n) × 100 % = 45 %
18/n = 45/100;
n = 1800/45;
n = 40
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The answer would be log base 2 of 6 over log base 2 of 3
Answer:
32 cm^3
Step-by-step explanation:
The cube is 4 across by 4 high by 2 wide
4*4*2 = 32 cm^3
