The population function of the Western Lowland Gorillas can either represent population growth or population decay
<h3>How to model the population</h3>
The question is incomplete, as the resources to model the population of the Western Lowland Gorillas are not given.
So, I will give a general explanation to solve the question
A population function can be represented as:

Where:
- The initial population of the Western Lowland Gorillas is represented by (a)
- The rate at which the population changes is represented by (r)
- The number of years since 2022 is represented by (x)
- The population in x years is represented by (y)
From the question, we understand that the population of the Western Lowland Gorillas decreases.
This means that the rate of the function would be an exponential decay i.e. 1 -r
Take for instance:

By comparison.
a = 2000 and 1 - r = 0.98
The above function can be used to model the population of the Western Lowland Gorillas
Read more about exponential functions at:
brainly.com/question/26829092
Average Density (150 – 250 square feet per employee): Mix of ... Common Areas & Conference Rooms ... that often present to clients or have large team meetings .
Answer: 
Step-by-step explanation:
We know that:
: The number of vibrations per second of the nylon guitar string.
: Tension.
: The length of the string.
Since
varies directly with the square root of the
and inversely with
, the equation has the following form:

Where "k" is the constant of variation.
Knowing that when
and
,
, we can find the value of "k":

Finally, in order to find the tension when the length is 0.3 meters and the number of vibrations is 12, you need to substitute these values and the value of "k" into
and solve for
:

Answer:
x + 2700 ≥ 5000 → x ≥ 2300
Step-by-step explanation:
The inequality is: x + 2700 ≥ 5000 with x being the number of points
To solve we need to subtract 2700 from both sides to get: x ≥ 2300