Answer:
1
Step-by-step explanation:
Given :
Mean, μ = 4
Standard deviation, s = 0.8
Sample size, n = 30
The distribution is independent.
Z = (x - μ) / s /sqrt(n)
Probability that downtime period is between 1 and 5
P(1≤ x ≤ 5) :
[(x - μ) / (s /sqrt(n))] ≤ Z ≤ [(x - μ) / (s /sqrt(n))]
[(1 - 4) / (0.8 /sqrt(30))] ≤ Z ≤ [(5 - 4) / (0.8 /sqrt(30)]
[-3 / 0.1460593] ≤ Z ≤] 1 / 0.1460593]
P(-20.539602 ≤ Z ≤ 6.8465342)
P(Z ≤ 6.8465342) - P(Z ≤ - 20.5396)
P(Z ≤ 6.8465342) = 1 (Z probability calculator)
P(Z ≤ - 20.5396) = 0 (Z probability calculator)
1 - 0 = 1
I'm gonna go with triangular pyramid and a cylinder
if this is an actual question could you give the whole thing?
Answer:
D
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - 3, thus
y = - 3x + c ← is the partial equation
To find c substitute (2, - 5) into the partial equation
- 5 = - 6 + c ⇒ c = - 5 + 6 = 1
y = - 3x + 1 → D
