In order to find the vector that points from A to B we need to subtract each component of A from the corresponding component of B, according to the formula:
v(a→b)=(b1−a1,b2−a2)
In this case we have :
v(a→b)=(−5−(−8),3−(−1))
<span>v(a→b)=(3,4)
</span>To find the magnitude we use the formula:
||v|= √(v1^2)+(v1^2)
So:
||v|= √(32)+(42)
||v|= √9+16
||v|= <span>√</span>25
||v|= 5
Answer:
A
Step-by-step explanation:
Given
p² + 2p - 8 = 0 ← in standard form
with a = 1, b = 2, c = - 8
Using the quadratic formula to solve for p
p = ( - 2 ±
/ 2
= ( - 2 ±
/ 2
= ( - 2 ±
) / 2
p =
=
= - 4
p =
=
= 2
Since its to the tenth power and the exponent is negative all you have to do is move the decimal point two positions back and your new answer is 0.382
Vertex: (-5,-2); parabola opens up;
General form of the equation for a vertical parabola opening up is:
y-k = a(x-h)^2; knowing that the vertex is at (-5,-2), we can write:
y+2 = a(x+5)^2. We need to find the value of the coefficient a.
From the graph we see that y is 10 when x is approx. -1 3/4 (or -7/4).
subst. these values into y+2 = a(x+5)^2, we get:
10 + 2 = a(-7/4 + 5)^2, or 12 = a(13/4)^2, or 1 = a(169/16).
Solving for a: a = 16/169 = 0.09, or approx 16/160, or 1/10. Unfortunately, this is not close to any of the four answer choices.
I thought it best to try again, and fortunately my second try was correct:
10+2 = a(13/4)^2, or (169/16)a. Thus, 12 = a(169/16)
12
Solving for a: a = ------------- = 1.14. The answer choice closest to this is 1.
169/16
Answer A is correct.