Answer:
-3
Step-by-step explanation:
Answer:
Just the second one is correct
The solutions are
.
Solution:
Given equation:

Add
on both sides.

-------- (1)
(given) -------- (2)
Equate (1) and (2).

Add
on both sides.


Add 5 on both sides.


Divide by 5 on both sides, we get

Taking square root on both sides, we get

Substitute
in (1).



Substitute
in (1).



Therefore the solutions are
.
Option C is the correct answer.
Answer:
Probability that average height would be shorter than 63 inches = 0.30854 .
Step-by-step explanation:
We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.
Also, a random sample of 4 women from this population is taken and their average height is computed.
Let X bar = Average height
The z score probability distribution for average height is given by;
Z =
~ N(0,1)
where,
= population mean = 64 inches
= standard deviation = 4 inches
n = sample of women = 4
So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)
P(X bar < 63) = P(
<
) = P(Z < -0.5) = 1 - P(Z <= 0.5)
= 1 - 0.69146 = 0.30854
Hence, it is 30.85% likely that average height would be shorter than 63 inches.
Yes they can if 7 + 7 equals more then 11 the. The answer is yes