Answer:
I only do Design and Technology
sorry don't understand.
The primary source of help for technical problems with BC Online (computer settings, password, etc.) is: The Instructor
<h3>Computer Technical Problems</h3>
Usually when we have problems on our computers, depending on the type of problem we can call the attention of a technician or follow the advice of an instructor or the message prompt on the software or website.
However, when it comes to technical problems such as Computer settings or password, we have to make sure we follow the instructions given by the instructor primarily especially because BC Online from the question is a type of Government Registry Information that is used by the citizens with the aid of instructors.
Read more on computer technical problems at;
brainly.com/question/17506968
Answer:
Step by step explanation along with code and output is provided below
Explanation:
#include<iostream>
using namespace std;
// print_seconds function that takes three input arguments hours, mints, and seconds. There are 60*60=3600 seconds in one hour and 60 seconds in a minute. Total seconds will be addition of these three
void print_seconds(int hours, int mints, int seconds)
{
int total_seconds= hours*3600 + mints*60 + seconds;
cout<<"Total seconds are: "<<total_seconds<<endl;
}
// test code
// user inputs hours, minutes and seconds and can also leave any of them by entering 0 that will not effect the program. Then function print_seconds is called to calculate and print the total seconds.
int main()
{
int h,m,s;
cout<<"enter hours if any or enter 0"<<endl;
cin>>h;
cout<<"enter mints if any or enter 0"<<endl;
cin>>m;
cout<<"enter seconds if any or enter 0"<<endl;
cin>>s;
print_seconds(h,m,s);
return 0;
}
Output:
enter hours if any or enter 0
2
enter mints if any or enter 0
25
enter seconds if any or enter 0
10
Total seconds are: 8710
Answer:
3,265,920 unique ID exist.
Explanation:
The nine digits are from 0 to 9, there are ten bits from 0 -9,
0, 1, 2, 3, 4, 5, 6, 7, 8, 9
The first is select from the highest bit (9), and the second is selected at random from 0 - 9, the third bit to the last must be unique and different from each other;
number of unique IDs = 9 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2
Multiplying the nine bits of unique IDs = 3,265,920.