Answer: using t - test value is 1.37<2.08( At 0.05 level of significance)
The mean of the sample was drawn from the population.
Step-by-step explanation:
Here sample size n=22
Given sample mean =530
Given population mean =500

given sample standard deviation s=100
<u>a) null hypothesis</u>:- The mean of the sample was drawn from the population µ =500
<u>Alternative hypothesis</u>:-
The most powerful test you can use is t - distribution.
The test statistic is
![t=\frac{sample mean- µ}{\frac{S}{\sqrt{n-1} } } here S is the standard deviation of the sampleb) The value of the test statistic [tex]t=\frac{sample mean- µ}{\frac{S}{\sqrt{n-1} } } substitute given values sample size n=22sample mean =530sample standard deviation s =100mean of the population µ =500the calculated value of t =[tex]\frac{530-500}{\frac{100}{\sqrt{22} } }](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bsample%20mean-%20%C2%B5%7D%7B%5Cfrac%7BS%7D%7B%5Csqrt%7Bn-1%7D%20%7D%20%7D%20%20%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3Ehere%20S%20is%20the%20standard%20deviation%20of%20the%20sample%3C%2Fp%3E%3Cp%3Eb%29%20%20The%20value%20of%20the%20test%20statistic%20%3C%2Fp%3E%3Cp%3E%20%20%20%20%20%20%20%20%20%20%20%20%5Btex%5Dt%3D%5Cfrac%7Bsample%20mean-%20%C2%B5%7D%7B%5Cfrac%7BS%7D%7B%5Csqrt%7Bn-1%7D%20%7D%20%7D%20%20%3C%2Fp%3E%3Cp%3Esubstitute%20given%20values%20sample%20size%20n%3D22%3C%2Fp%3E%3Cp%3Esample%20mean%20%3D530%3C%2Fp%3E%3Cp%3Esample%20standard%20deviation%20s%20%3D100%3C%2Fp%3E%3Cp%3Emean%20of%20the%20population%20%C2%B5%20%3D500%3C%2Fp%3E%3Cp%3Ethe%20calculated%20value%20of%20t%20%3D%5Btex%5D%5Cfrac%7B530-500%7D%7B%5Cfrac%7B100%7D%7B%5Csqrt%7B22%7D%20%7D%20%7D)
the calculated value=1.3748
c) The degrees of freedom =n-1 = 22-1 = 21
The table value of t are 0.05 level of significance with 21 degrees of freedom is <u>2.08</u>
The calculated value 1.37<2.08
∴ we accept null hypothesis at 0.05 level of significance
<u>conclusion:-</u>
The mean of the sample was drawn from the population.
Given a triangle with side lengths of 3, 4 and 5. This gives a right triangle with legs of length 3 and 4 and hypothenus of length 5.
Given a triangle with side lengths of 5, 12 and 13. This gives a right
triangle with legs of length 5 and 12 and hypothenus of length 13.
a.) The sum of the measures of the acute angles of any right triangle is 90 degrees. This is because, for a right triagle, one of the angles is a right angle which is 90 degrees and the sum of the interior angles of a triangle is 180 degrees. Thus the other two angles of a right triangle sums up to 180 - 90 = 90 degrees.
b.) The tangent ratio of a right triangle is the ratio of the legs of the triangle. (i.e. the sides of the right triangle other than the hypothenus).
For the first right triangle with side lengths of 3, 4 and 5 units, the tangent ratios are 3/4 and 4/3.
c.) Similarly, for the second reight triangle with side lengths of 5, 12 and 13 units, the tangent ratios are 5/12 and 12/3.
d.) The rule describing <span>the relationship between the tangents of the acute angles of any right triangle is given by

where: 'opposite' refers to the side opposite the angle of reference and </span> 'adjacent' refers to the side (other than the hypothenus) adjacent the angle of reference of the right triangle.
Answer:
=
Step-by-step explanation:
{0}={} because 0 means that there is nothing and in null set too, there is no elements.
Answer:
Step 1: Fold a piece of paper in half and determine the number of layers of paper. ... Number of Folds ... Step 3: Write a function for the number of layers of paper if you fold the paper n times. ... Step 7: A ream of paper is almost 2 inches thick. If a ... Step 11: Sketch a graph for the thickness of the stack, and label the axes.
Step-by-step explanation:
HERE YOU GO