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Ilya [14]
3 years ago
12

The gym teacher is setting up for a field

Mathematics
1 answer:
irinina [24]3 years ago
7 0
$630

The total perimeter is 42 and 42x15=630
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Find f(x) + g(x) for<br> [ f(x) = 6x – 4<br> [g(x) = -5x + 24
Ket [755]

Answer:

f(x) + g(x) = x + 20

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Functions
  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 6x - 4

g(x) = -5x + 24

<u>Step 2: Find f(x) + g(x)</u>

  1. Substitute in functions:                                                                                     f(x) + g(x) = 6x - 4 + (-5x + 24)
  2. Combine like terms (x):                                                                                    f(x) + g(x) = x - 4 + 24
  3. Combine like terms:                                                                                         f(x) + g(x) = x + 20
3 0
2 years ago
A student solved the following problem and made an error: Triangles ABC and DEF. Angles A and F are congruent and measure 135 de
dmitriy555 [2]
We have that
triangle ABC coordinates
A (0,2)  B(2,4)  C(0,0)

triangle DEF coordinates 
D (2,0)  E ( 4,4)  F (4,2)

using a graph tool
see the attached figure

therefore

Line 1<span> Segment AC equals 2. Segment FE equals 2. Segment AC is congruent to segment FE 
</span>so
Segment AC equals 2-------> is correct
Segment FE equals 2-----> is correct
Segment AC is congruent to segment FE------> is correct

<span>Line 2 ∠A ≅ ∠F------> is correct
</span>
<span>Line 3 Length of segment AB. A (0, 2) B (2, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8 segment AB = 2.83
</span>
find the distance AB
d=√[(4-2)²+(2-0)²]--------> d=√[4+4]-----> d=√8-----> d=2.83
AB=2.83
so
Line 3 is correct

<span>Line 4 Length of segment DE. D (2, 0) E (4, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20 segment DE = 4.47
</span>
find the distance DE
d=√[(4-0)²+(4-2)²]--------> d=√[16+4]-----> d=√20-----> d=4.47
DE=4.47
so
Line 4------> is correct

<span>Line 5 segment AB is congruent with segment DE
AB is not congruent with DE
so
Line 5 is not correct

therefore

the answer is
</span><span>the student make the first mistake in line 5</span><span>

</span>

6 0
3 years ago
carols bikes 1 kilometer east 4 kilometers north and then 5 kilometers east again. how far is caroll from her starting position
Volgvan
That'd be a total of 6 km east and 4 km north.

The distance traveled from Carol's starting point, along the path described, is
1 km + 4 km + 5 km = 10 km.

However, if you want the straight line distance from starting to end point, that would be found using the Pyth. Thm.:

sqrt [ (6 km)^2 + (4 km)^2 ] = sqrt(52) = 2sqrt(13) km
3 0
3 years ago
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As x decreases in value.f(x) decreases in value.......

8 0
3 years ago
Graph the equation y=x+7
Otrada [13]
HERE IT IS!!!


I HOPE THIS IS GOOD ENOUGH

8 0
3 years ago
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