Answer: using t - test value is 1.37<2.08( At 0.05 level of significance)
The mean of the sample was drawn from the population.
Step-by-step explanation:
Here sample size n=22
Given sample mean =530
Given population mean =500
given sample standard deviation s=100
<u>a) null hypothesis</u>:- The mean of the sample was drawn from the population µ =500
<u>Alternative hypothesis</u>:-
The most powerful test you can use is t - distribution.
The test statistic is
the calculated value=1.3748
c) The degrees of freedom =n-1 = 22-1 = 21
The table value of t are 0.05 level of significance with 21 degrees of freedom is <u>2.08</u>
The calculated value 1.37<2.08
∴ we accept null hypothesis at 0.05 level of significance
<u>conclusion:-</u>
The mean of the sample was drawn from the population.