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bagirrra123 [75]
3 years ago
13

If x = 1, y = 2 and z = 5, find the value of x 3 − y 3 − z 3

Mathematics
1 answer:
AVprozaik [17]3 years ago
4 0

Answer:

<em><u>{1}^{3}  -  {2}^{3}  -  {5}^{3}</u></em>

<em><u>{ - 6}^{3}</u></em>

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In the figure, lines a and b are parallel.
navik [9.2K]

Answer:

<h2>m∠2 = m∠1</h2><h2>m∠1 = 75°</h2>

Step-by-step explanation:

Look at the picture.

Vertical angles, corresponding angles, alternate exterior angles are congruent.

Supplementary angles add up to 180°.

5 0
3 years ago
PLEASE HELP ME I DO'T UNDERSTAND DIS MATh
sladkih [1.3K]

Answer:

60%

Step-by-step explanation:

A percent is technically just a fraction over 100.

To get that here, we simply divide the part (which is 1560 people) by the whole (which is 2600 people) and then multiply that by 100:

(1560 / 2600) * 100 = 0.6 * 100 = 60/100

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3 0
2 years ago
the regular price of a calculator is $15.40. it goes on sale for 30% off the regular price. what is the amount of savings on the
nikitadnepr [17]
( 30 / 100 ) * (15.40 ) = ( 3 / 10 )* (15.40) = 36.20 / 10 = 3.62$.
7 0
3 years ago
A = 4 units B= 3 units C= 3.5. D= 5 units
aliya0001 [1]

D would be the correct answer.

Explanation

a^2+b^2=c^2

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16+9

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4 0
3 years ago
Percentage grade averages were taken across all disciplines at a particular university, and the mean average was found to be 83.
Georgia [21]
Correct Ans:
Option A. 0.0100

Solution:
We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.

First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

z-score= \frac{90-83.6}{ \frac{8.7}{ \sqrt{10} } } \\  \\ &#10;z-score =2.326

So, 90 converted to  z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.

Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.
5 0
3 years ago
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