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sergiy2304 [10]
3 years ago
8

A car releases 19.6 pounds of carbon dioxide for every 1 gallon of gasoline burned. Estimate the number of pounds of carbon diox

ide released if 14.5 gallons are burned.
Mathematics
1 answer:
dezoksy [38]3 years ago
3 0
The answer is 300.
Hope this helps! :D
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There's a plane that flies at an altitude of 25,000 feet. There's a submarine that dives to a depth of 600 feet below sea level.
ella [17]
25,000 + 600 considering they would meet at 0, so they are 25,600 feet apart
8 0
4 years ago
A grocery store is offering a sale on bread and soup. Khalil buys four cans of soup and
Flura [38]

Answer:

a) cblo

2)$3.44

Step-by-step explanation:

4 cans and 3 loaves=11.67

8 cans and 1 loaf= 12.89.

Set up equation:

x=cans

y=loaves

4x+3y=11.67\\8x+y=12.89 This is the answer for question A.

Multiply eq1 by 2:

8x+6y=23.34

Subtract eq3 by eq2:

5y=10.45\\y=2.09

Substitute:

8x+2.09=12.89\\8x=10.8\\x=1.35

One can of soup and one loaf of bread=

1.35+2.09 or 3.44

So:

$3.44

Hope this helps :D Please hit the crown if u can !!

6 0
3 years ago
Use a graphing utility to graph the function and the damping factor of the function in the same viewing window.
Bas_tet [7]

Answer:

The function touches the damping factor

at x=\frac{(4n-3)\pi}{2} and x=\frac{(4n-1)\pi}{2}

The x-intercept of f(x) is

at x=n\pi

Step-by-step explanation:

Given function is f(x)=e^{-3x} sin(x) and damping factor as y=e^{-3x} and y=(-1)e^{-3x}

To find when function touches the damping factor:

For f(x)=e^{-3x} sin(x) and y=e^{-3x}

Equating the both the equation,

e^{-3x} sin(x)=e^{-3x}

sin(x)=1

x=\frac{(4n-3)\pi}{2}

For f(x)=e^{-3x} sin(x) and y=(-1)e^{-3x}

Equating the both the equation,

e^{-3x} sin(x)=(-1)e^{-3x}

sin(x)=(-1)

x=\frac{(4n-1)\pi}{2}

Therefore, The function touches the damping factor x=\frac{(4n-3)\pi}{2} and x=\frac{(4n-1)\pi}{2}

To find x-intercept of f(x):

For x-intercept, y=0

f(x)=e^{-3x} sin(x)

y=e^{-3x} sin(x)

e^{-3x} sin(x)=0

Hence, e^{-3x} is always greater than zero.

Therefore,sin(x)=0

x=n\pi

Thus,

The x-intercept of f(x) is at x=n\pi

7 0
4 years ago
[15 ÷ 5 • 3 + (2³ – 3)] + [4 • (36 – 3³)]
liubo4ka [24]

Answer:

50

Step-by-step explanation:

[15 ÷ 5 • 3 + (2³ – 3)] + [4 • (36 – 3³)]

[3 × 3 + (8 - 3)] + [4 × (36 - 27)]

(9 + 5) + (4 × 9)

14 + 36

50

3 0
3 years ago
Read 2 more answers
Two isosceles triangles share the same base. Prove that the medians to this base are collinear. (There are two cases in this pro
Anna71 [15]

Answer:

Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.

To prove: Point A,D,P are collinear.

Proof:

→Case 1.  When vertices A and P are opposite side of Base BC.

In Δ ABD and Δ ACD

AB= AC   [Given]

AD is common.

BD=DC  [median of a triangle divides the side in two equal parts]

Δ ABD ≅Δ ACD [SSS]

∠1=∠2 [CPCT].........................(1)

Similarly, Δ PBD ≅ Δ PCD [By SSS]

 ∠ 3 = ∠4 [CPCT].................(2)

But,  ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]

2 ∠2 + 2∠ 4=360° [using (1) and (2)]

∠2 + ∠ 4=180°

But ,∠2 and ∠ 4 forms a linear pair i.e Point D is common point of intersection of median AD and PD of ΔABC and ΔPBC respectively.

So, point A, D, P lies on a line.

CASE 2.

When ΔABC and ΔPBC lie on same side of Base BC.

In ΔPBD and ΔPCD

PB=PC[given]

PD is common.

BD =DC [Median of a triangle divides the side in two equal parts]

ΔPBD ≅ ΔPCD  [SSS]

∠PDB=∠PDC [CPCT]

Similarly, By proving ΔADB≅ΔADC we will get,  ∠ADB=∠ADC[CPCT]

As PD and AD are medians to same base BC of ΔPBC and ΔABC.

∴ P,A,D lie on a line i.e they are collinear.




3 0
3 years ago
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