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dalvyx [7]
2 years ago
15

Please answer correct with an explanation thanks!

Mathematics
2 answers:
soldi70 [24.7K]2 years ago
8 0
17/50
There are 7 red rings, and there are 10 purple rings, If you add all the rings together, it is out of 50, therefore it is 17/50
Strike441 [17]2 years ago
3 0

Answer:

17/50

Step-by-step explanation:

P(red or purple) = number of red or purple / total

There are 7 red rings and 10 purple rings

                          = (7+10) / 50

                          = 17/50

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givi [52]
A. 2/5
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Which of the following graphs of exponential functions corresponds to a geometric sequence with a first term of 4 and a ratio of
ser-zykov [4K]

Answer: graph E.


A geometric sequence can be written as:

a_{n} = a_{1} \cdot r^{(n - 1)}

where:

a₁ = first term = 4

r = ratio = 0.5


Substituting the numbers, we have:

a_{n} = 4 \cdot (\frac{1}{2})^{n-1}

or else

f(x) = 4 \cdot (\frac{1}{2})^{x - 1}


This is an exponential function with base less than 1. Therefore, we can exclude graph C (which depicts a linear function), and graphs A and D (which depict an exponential function with base greater than 1).


In order to choose between graph B and E, let's evaluate the function in two different points:

f(1) = 4 \cdot (\frac{1}{2})^{1 - 1} = 4

f(2) = 4 \cdot (\frac{1}{2})^{2 - 1} = 4 \cdot \frac{1}{2} = 2


Therefore, we need to look for the graph passing through the points (1, 4) and (2, 2). That is graph E.




3 0
3 years ago
Read 2 more answers
Which of the following equations is equivalent to log(y)= 3.994 ?
Kisachek [45]

Answer:

The correct answer is option D: y = 10^{3.994}

Step-by-step explanation:

Given:  

log(y)= 3.994

Solution:

A logarithm base b of a positive number x satisfies the following definition:

y =log_b(x) => b^y =x

For x > 0, b >0, b \neq 1

Also if no base  b  is indicated, the base of the logarithm is assumed to be  10 .

Thus, in log(y)= 3.994 base b is not indicated. so its base is assumed to be 10

now

log_{10}(y)= 3.994

Then

y = 10^{3.994}

4 0
2 years ago
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3 years ago
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What what is the standard and expanded form of 3 billion 630 2900058
algol [13]
3,000,000,000,000+600,000,000+30,000,000+200,000+90,000+50+8
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