Please answer correct with an explanation thanks!

Mathematics

2 answers:

soldi70 [24.7K]2 years ago

8 0

17/50
There are 7 red rings, and there are 10 purple rings, If you add all the rings together, it is out of 50, therefore it is 17/50

Strike441 [17]2 years ago

3 0

Answer:

17/50

Step-by-step explanation:

P(red or purple) = number of red or purple / total

There are 7 red rings and 10 purple rings

= (7+10) / 50

= 17/50

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The graph of f(x) = x2 is translated to form g(x) = (x – 5)2 + 1. Which graph represents g(x)?

levacccp [35]

<span>The graph would be translated 5 units right and 1 unit up, giving an upward facing parabola with a vertex at (5, 1).

Explanation:
Since 5 was subtracted from x before it was squared, this means a horizontal translation 5 units. Since it was subtracted, this means it was translated right 5 units.

The 1 added at the end means it was translated 1 unit up as well.

This is in vertex form, y=a(x-h)^2 + k, where (h, k) is the vertex; h corresponds with 5 and k corresponds with 1, so the vertex is at (5, 1).</span>

6 0

3 years ago

Read 2 more answers

You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along

sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

$d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}$

Then, the time (speed divided by distance) is:

$t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1$

To optimize this function we have to derive and equal to zero:

$\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\ \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\$

$x$

As $d_b=x$ , the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.