PLS HELP ASAP What are the possible rational zeros of f(x) = x4 + 2x3 − 3x2 − 4x − 12?
1 answer:
You might be interested in
Answer:
(0, 1).
Method 1 (Substitution):
Substituting our two y's, we get the following:
Thus, the only set of solutions is (0, 1). A quick sketch (either by hand or on Desmos) can confirm this.
Method 2 (Elimination):
We have two equations. We'll let the top one be equation 1 and the bottom one be equation 2. Eliminating as many variables as we can, we subtract (2) from (1) to get:
0 = 3x => x = 0.
So the only set of solutions is (0, 1).
Method 3 (Gaussian elimination):
We can place this in an augmented matrix and row reduce.
Row reducing this gives us:
This tells us that the only solution for x is x = 0 (since we read this as "3x = 0") and thus, the only solution we get is (0, 1).
<h2>○=> <u>Solution (6)</u> :</h2>
Ratio of two numbers = 2:3
The larger number = 6
Let the smaller number be x.
Which means :
▪︎<u>Therefore, the smaller number = 4</u>
<h2>○=> <u>Solution (7)</u> :</h2>36 compared to 6 =
Let the number be x.
Which means :
▪︎Therefore, the fractional number is equal to
.
Number of Rose's for 24 red Rose's = 6
This can be written in a ratio as 24:6
Number of roses = 8
Let the number of red roses for these roses be x.
Which means :
▪︎Therefore, 32 red roses are there if there are 8 roses.
<h2>○=> <u>Solution (9)</u> :</h2>Number of children for 2 adults = 7
This can be written in a ratio as 7:2
Number of children in the plaza = 21
Let the number of adults be x.
Which means :
▪︎Therefore, 6 adults were there in the plaza.
<h2>○=> <u>Solution (10)</u> :</h2>Cost of 12 pencils = P60
Cost of 1 pencil :
Thus, the cost of one pencil = P5
Cost of 25 pencils :
= Cost of one pencil × 25
▪︎Therefore, the cost of 25 pencils = P125