Answer:
OPTION B) 2ab
Step-by-step explanation:
Given:
Side of larger square = (a + b) units
Side of smaller square = c units
To Find:
The area of all four triangles combined = ?
Solution:
a^2 + b^2 = c^2 (Pythagoras theorem) -(1)
The area of all four triangles combined = Area of larger square - Area of smaller square
The area of all four triangles combined = (a + b)^2 - c^2
The area of all four triangles combined = a^2 + b^2 + 2ab - (a^2 + b^2) {By (1)}
The area of all four triangles combined = a^2 + b^2 + 2ab - a^2 - b^2
The area of all four triangles combined = a^2 - a^2 + b^2 - b^2 + 2ab
Therefore, The area of all four triangles combined = 2ab sq. units
OPTION B) 2ab
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Answer:
Step-by-step explanation:
The picture attached is the complete question for this problem while the word file attached is the solution to the problem.
Answer:
4,5,6 are the three consecutive numbers. 16, 25 and 36 are their squares.
Step-by-step explanation:
Let the three consecutive numbers be x, (x+1), (x+2)
Now, the squares of these three numbers are
Sum = 77
∴by the problem ,
{Taking 3 common }
{By factorization}
Therfore,
<em>X can't be negetive </em>
∴
The squares of the three consecutive numbers are 16, 25, 36
The three consecutive numbers whose sum is 77 are 4, 5, 6
Answer:
56
Step-by-step explanation:
Answer:
72
Step-by-step explanation:
you do this this then this. did it help?