Answer:
29 is answer.
Step-by-step explanation:
Given that the function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237.
To find average velocity of the object over the interval of time [1,3]
We know that derivative of s is velocity and antiderivative of velocity is position vector .
Since moving along a line equation of s is
use two point formula
gives the position at time t.
Average velocity in interval (1,3)
=![\frac{1}{3-1} (s(3)-s(1))\\=\frac{1}{2} [87+58-29-58]\\=29](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3-1%7D%20%28s%283%29-s%281%29%29%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%20%5B87%2B58-29-58%5D%5C%5C%3D29)
Solution :
It is given that four different prizes were awarded. So,
a). 4 ways for person 47 to win a prize
99 ways to give out the 2nd prize
98 ways to give the 3rd prize
97 ways to give the last prize
∴ P(99,3) = 99 x 98 x 97
b). 1 way to give person 47 their prize
1 way to give person 19 their prize
98 ways to give out the 3rd prize
97 ways to give out the last prize
So, P(98,2) = 98 x 97
Answer:
141.291667 or about 141
Step-by-step explanation:
Hey there! I'm happy to help!
First, let's find the area of the top of the bar.
30×70=2100
This is the same as the bottom of the bar, so we have another 2100 mm, giving us 4200 in total.
Now we want to find the two long sides. This is 70×4.5, which is 315. Since there are two of these sides, we have another 315, giving us 630 in total there.
Now we have the short sides.
30×4.5=135
135×2=270
Now, we add up all of these measurements.
4200+630+270=5100
Therefore, Will's Wrapping Company will need 5100 mm² of paper to make their wrapper.
Have a wonderful day! :D
5w+12=67
-12 -12
5w=55
w=11
first, subtract 12 from both sides. second, divide 5 on both sides
