The moment magnitude scale is a scale that rates earthquakes by estimating the total energy released by an earthquake . Estimating the total amount of energy released, enables comparison of earthquakes more accurately.
This scale can be used to rate earthquakes of all sizes, near or far. The following statements describe the moment magnitude scale:
B. It collects data using a seismograph.
D. It estimates the total energy released from an earthquake.
E. It determines the amount of damage caused by an earthquake.
Answer: Option (a) is the correct answer.
Explanation:
A lipid that contains a phosphate group in its molecule is known as a phospholipid.
These are the primary molecules present in a plasma membrane. These tend to contain two hydrophobic fatty acid tails and one hydrophilic head.
Hydrophilic means water loving in nature.
As phosphate group is a polar group due to this the hydrophilic region present in a phospholipid is able to interact with water.
In an amino-alcohol modified phosphate, ester groups, and glycerol, the glycerol is hydrophobic in nature. It also contains two fatty acids and a phosphoric acid which are present as ester. The polar head that mainly consists of phosphate group is hydrophilic and thus, it helps in combining to a water molecules.
Hence, we can conclude that in a phospholipid, amino-alcohol modified phosphate, ester groups, and glycerol are the components which constitute the hydrophilic head.
Answer:
magnesium+ hydrochloric acid is the reactants
Explanation:
the reactants are always in the left and the products are always in the right by
magnesium+hydrochloric acid ⇒ magnesium chloride + hydrogen
by combining magnesium and hydrochloric acid it produces magnesium chloride and hydrogen.
hope this helps..
Answer:
337.22 K
Explanation:
Given that:
P₁ = 1 atm
T₁ = 350 K
P₂ = 0.639 atm
T₂ = ??? (unknown)
R(rate constant) = 8.34 J k⁻¹ mol⁻¹
Using Clausius-Clapeyron equation, we can determine the final boiling point of the process.
Clausius-Clapeyron equation can be written as:
![In\frac{P_2}{P_1}=\frac{\delta H_{vap}}{R}[\frac{T_2-T_1}{T_2T_1}]](https://tex.z-dn.net/?f=In%5Cfrac%7BP_2%7D%7BP_1%7D%3D%5Cfrac%7B%5Cdelta%20H_%7Bvap%7D%7D%7BR%7D%5B%5Cfrac%7BT_2-T_1%7D%7BT_2T_1%7D%5D)
Substituting our values given; we have:
![In\frac{0.639}{1}=(\frac{34.4*10^3J/mol}{8.314 J K^{-1}mol^{-1}})[\frac{T_2-350}{350T_2}]](https://tex.z-dn.net/?f=In%5Cfrac%7B0.639%7D%7B1%7D%3D%28%5Cfrac%7B34.4%2A10%5E3J%2Fmol%7D%7B8.314%20J%20K%5E%7B-1%7Dmol%5E%7B-1%7D%7D%29%5B%5Cfrac%7BT_2-350%7D%7B350T_2%7D%5D)
![In({0.639})=(\frac{34.4*10^3}{8.314K^{-1}})[\frac{T_2-350}{350T_2}]](https://tex.z-dn.net/?f=In%28%7B0.639%7D%29%3D%28%5Cfrac%7B34.4%2A10%5E3%7D%7B8.314K%5E%7B-1%7D%7D%29%5B%5Cfrac%7BT_2-350%7D%7B350T_2%7D%5D)
![- 0.4479 = 41317.599 [\frac{T_2-350}{350T_2} ]K](https://tex.z-dn.net/?f=-%200.4479%20%3D%2041317.599%20%5B%5Cfrac%7BT_2-350%7D%7B350T_2%7D%20%5DK)
![-\frac{0.4479}{4137.599} = [\frac{T_2-350}{350T_2} ]](https://tex.z-dn.net/?f=-%5Cfrac%7B0.4479%7D%7B4137.599%7D%20%3D%20%5B%5Cfrac%7BT_2-350%7D%7B350T_2%7D%20%5D)
![- 1.0825118*10^{-4} = [\frac{T_2-350}{350T_2} ]](https://tex.z-dn.net/?f=-%201.0825118%2A10%5E%7B-4%7D%20%3D%20%5B%5Cfrac%7BT_2-350%7D%7B350T_2%7D%20%5D)
∴ the boiling point of CH3COOC2H5 when the external pressure is 0.639 atm is <u>337.22</u> K.
