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3 years ago

(X-2)(x^2+2x+4) what is the answer to this equation?

2 answers:

8 0

First we expand by distributing sum groups
X(x^2 + 2x + 4 ) - 2 (x^2 + 2x + 4)
Then you expand by distributing terms
X^3 + 2 x^2 + 4x - 2 ( x^2 + 2x + 4)
Collect like terms
X^3 + (2x^2 - 2x^2) + (4x - 4x) - 8
Simplify
X^3 - 8

Delvig [45]3 years ago

7 0

Answer:

x^3 - 8

Step-by-step explanation:

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The dimensions of a triangular prism are shown below what is the volume of the prism in cubic feet

Yuliya22 [10]

Answer:

B. 192.5 ft³

Step-by-step explanation:

To find the volume of a triangle prism, multiply the base, height, and length together, and then divide it by 2 (or multiply that by 0.5).

(5 * 7 * 11)/2

Multiply 5 by 7 to get 35.

(35 * 11)/2

Multiply 35 by 11 to get 385.

385/2

192.5 ft³ is the volume of this triangluar prism.

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Penelope buys bracelets in bulk at a cost of $8 each to sell at her store. She uses a markup rate of 125%, which is added to the

slega [8]

Answer:

$18.00

Step-by-step explanation:

8 x 1.25 = 10

8 + 10 = 18

5 0

3 years ago

PLEASE HELP ANYONE.....

irga5000 [103]

Answer:

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3 years ago

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Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago