Answer:
compare the distance between the lines at one point to the distance between the lines at another point
Step-by-step explanation:
You can construct perpendiculars at different points and compare the distance between the lines at those perpendiculars. The distance between parallel lines is the same everywhere.
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
c but you have it so thanks
Step-by-step explanation:
The answer is 14. The two lower angles are 50 each 100 total and so the top angle must equal 80. If you set it equal to 80 you get 14.
Hello,
Dividing by 0 is not defined so let s take x different from 4 and -4 and then we can write:
As
Thanks
