This answer is a equation, my teacher told me this
Assuming you pick 3 students at random, The probability that at least two plan on attending college is 84%.
<h3>Probability</h3>
Using Binomial Distribution
Given:
n = 3
p = 0.75
q = 1-0.95 = 0.25
Hence:
P[≥2] = P[2] + P[3]=(3c2 ×0.75²×0.25) + 0.75³
P[≥2] = P[2] + P[3]=0.421875+0.421875
P[≥2] = P[2] + P[3]=0.84375×100
P[≥2] = P[2] + P[3]=84% (Approximately)
Inconclusion the probability that at least two plan on attending college is 84%.
Learn more about probability here:brainly.com/question/24756209
Answer:
the probability that no customer will arrive in the next 6 minutes = 0.36788 = 0.368
Step-by-step explanation:
If there are 10 customers per hour, this translates to 1 customer per 6 minutes
So, if there's a mean of 1 customer per 6 minutes, to obtain the probability that no customer will come in a 6 minute interval, this becomes a Poisson distribution problem.
The Poisson distribution formula is given by
P(X = x) = (e^-λ)(λˣ)/x!
where λ = mean = 1 customer per 6 minutes
x = 0 customer per 6 minutes
P(X=0) = (e⁻¹)(1⁰)/0! = 0.36788 = 0.368
-4(-5-b)=1/3(b+16) Multiply both sides by 3 to get rid of the fraction
-12(-5-b)=b+16 distribute the -12 to get rid of the parenthesis
60+12b=b+16 get the b on the left side and non b values to the right side
11b=-44 solve for b
b=-44/11 simplify the fraction
b=-4
3/5(t+18)=-3(2-t) multiply both sides by 5/3 to get rid of thefraction
t+18=-5(2-t) distribute the -5 to get rid of the parenthises
t+18=-10+5t get the t to the left side and non t values to the right
-4t=-28 solve for t
t=7
If Bobby claims Peter started with 21 cards, then we'll work this into our equation.
21 - 3 (that he lost) = 18
18 / 2 (the half he gave) = 9
So this means that he did have 21 cards to begin with. Please reply to this with a list of the answers that can/could be checked!
