Answer:
1/4
Step-by-step explanation:
Assuming the number cube is a six-faced die, you have
1 <u>2</u> 3 <u>4</u> 5 <u>6</u>
three odd numbers, and three even numbers. Therefore, the chance of it landing on an odd number or even number is 3/6, which equals 1/2. <em>That means you have a 50% chance to get an odd number, or an even number.</em>
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So, you have two die. Both have a 50/50 chance of getting an even or odd number. So what's the chance of one landing on an odd number, and the other landing on an even number?
- You would have a 25% chance for an <u>even</u> and then an <u>even</u> number
- You would have a 25% chance for an <u>odd</u> and then an <u>odd</u> number
- You would have a 25% chance for an <u>even</u> and then an <u>odd</u> number
- You would have a 25% chance for an <u>odd</u> and then an <u>even</u> number.
25% as a simplified fraction is 1/4. Therefore, 1/4 is your answer.
F(1) = -5(1)^2+2(1)+9 = 6
f(2) = -5(2)^2+2(2)+9 = -9
So, because f(1) = 6 is positive and f(2) = -9 is negative, f(1) > f(2).
f(1) is greater than f(2)!
The answer would actually be a 110 units because the bottom left corner had 20 units and the bigger square had 90.
