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azamat
3 years ago
10

Am I correct?? I did not count the last square unit at the vertices of each corner.

Mathematics
1 answer:
mariarad [96]3 years ago
3 0
The answer would actually be a 110 units because the bottom left corner had 20 units and the bigger square had 90.
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Hii I need help with these questions tyy!
9966 [12]

Answer:

(7x+2)(3x-1); (5x+4)^2 or (5x+4)(5x+4);

Step-by-step explanation:

formula to find area is L* W = A ; meaning length multiplied by width equals to the area.

21.

using the formula to find area...

l*w=a

(7x+2)(3x-1) would be your answer

btw, don't put the "=a" at the end, since it's an expression :))

22.

since the problem states that it's a square, you can just say either...

(5x+4)^2 or (5x+4)(5x+4) not sure which one your teacher accepts

4 0
2 years ago
Read 2 more answers
Pl help it’s for a grade
allsm [11]

Answer:

(^6√x^5) (√y)

(The 6 belongs in the left on top of the square root btw)

For x the 6 moves to the front of the square root while the 5 becomes the power of x.

For y, the power to the 1/2 is the same as a square root.

5 0
3 years ago
What is the smallest multiple 3 and 4 have in common
murzikaleks [220]
Their least common multiple is 12.
8 0
3 years ago
A person is on the outer edge of a carousel with a radius of 20 feet that is rotating counterclockwise around a point that is ce
lubasha [3.4K]
<h2>Answer:</h2>

\boxed{(5(-\sqrt{2}+\sqrt{6}),5(\sqrt{2}+\sqrt{6}))}

<h2>Step-by-step explanation:</h2>

The origin of the coordinate system is the center of the circle. So we have an angle that measures 5\pi/12=75^{\circ}. so the x-coordinate and y-coordinate can be found, by using trigonometry as follows:

x=20cos(5\pi/12)=5\sqrt{6}-5\sqrt{2} \\ \\ Arranging:\\ \\x=5(-\sqrt{2}+\sqrt{6}) \\ \\y=20sin(5\pi/12)=5\sqrt(6)+5\sqrt{2} \\ \\ Arranging:\\ \\y=5(\sqrt{2}+\sqrt{6})

Finally, the exact value of the position of the rider after the carousel rotates 5\pi/12 radians is:

\boxed{(5(-\sqrt{2}+\sqrt{6}),5(\sqrt{2}+\sqrt{6}))}

3 0
3 years ago
What is the inverse function of f(x)=2x-1
Goshia [24]

Step-by-step explanation:

Given

f(x) = 2x - 1

f^-1 (x) = ?

Now

Let y = f(x)

or y = 2x - 1

Interchanging the role of x and y

x = 2y - 1

x + 1 = 2y

y = <u>x </u><u>+</u><u> </u><u>1</u>

2

Therefore f^-1(x) = <u>x </u><u>+</u><u> </u><u>1</u>

2

Hope it will help you :)

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3 years ago
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