Exercise 1:
exponential decay:
The function is given by:
y = A (b) ^ ((1/3) * t)
Where,
A = 600
We look for b:
(480/600) * (100) = 80%
b = 0.8
Substituting:
y = 600 * (0.8) ^ ((1/3) * t)
We check for t = 6
y = 600 * (0.8) ^ ((1/3) * 6)
y = 384
Answer:
exponential decay:
y = 600 * (0.8) ^ ((1/3) * t)
Exercise 2:
linear:
The function is given by:
y = ax + b
Where,
a = -60 / 2 = -30
b = 400
Substituting we have:
y = -30 * x + 400
We check for x = 4
y = -30 * 4 + 400
y = 280
Answer:
linear:
y = -30 * x + 400
Exercise 3:
exponential growth:
The function is given by:
y = A (b) ^ ((1/3) * t)
Where,
A = 512
We look for b:
(768/512) * (100) = 150%
b = 1.5
Substituting:
y = 512 * (1.5) ^ ((1/2) * t)
We check for t = 4
y = 512 * (1.5) ^ ((1/2) * 4)
y = 1152
Answer:
exponential growth:
y = 512 * (1.5) ^ ((1/2) * t)
Answer:
Step-by-step explanation:
Check attachment for answers.
When you solve the following equation, solving for the quadratic formula.
The answer is; x=4
Next time pay attention in class.
Answer: SuLee jumped 2.50 more feet farther than Nate.
Step-by-step explanation: 12.75 - 10.25 = 2.50
Step-by-step explanation:
you are "hiding" some more information (like how much they made together).
without that we cannot calculate the actual values.
all I can do is set up the equations expressing the given relations between the parts of the total :
a = amount Alberto made
b = amount Benjamin made
c = amount Carlota made
b = 3×a
c = 2×b = 2× 3×a = 6×a
that's it.
your see ? now we need something that "ties" all 3 together, an equation of all 3 variables, where we can use the first 2 equations (by substitution) and then solve for the remaining third variable.
and that is missing.
if it is something like "together they made x", then we would have
a + b + c = x
a + 3a + 6a = x
10a = x
a = x/10
b and c we get then from the first 2 equations by simply using the calculated value of a :
b = 3×(x/10) = 3x/10
c = 6×(x/10) = 6x/10 = 3x/5
