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soldi70 [24.7K]
1 year ago
13

identify the type i error and the type ii error that corresponds to the given hypothesis. the proportion of people who write wit

h their left hand is equal to 0.29 .
Mathematics
1 answer:
djverab [1.8K]1 year ago
3 0

Type I error is:

" Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29 "

Type II error is:

"Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually different from 0.29 "

<u>What is proportion?</u>

An equation in which two ratios are made equal is called a proportion. For instance, you could write the ratio as 1: 3 (for every one boy, there are three girls), which means that 14 of the population is made up of boys and 34 of the population is made up of girls.

In Statistics, a  type I error is the rejection of a true null hypothesis

and  a type II error is the non-rejection of a false null hypothesis

Given that p = 0.29 is accepted

Now type I error is

C. Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29

i.e. (false positive)

and type II error here is

B. Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually different from 0.29.

To learn more about the proportion from the given link

brainly.com/question/19994681

#SPJ4

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strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

x^2 + 11x - 4 = 0

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}

where x_{1,2} is a compact way to indicate both solutions x_1 and x_2, while a,b,c are the coefficients of the quadratic equation, i.e. we consider the polynomial ax^2+bx+c.

So, in your case, we have a=1,\ \ b=11,\ \ c=-4

Plug those values into the formula to get

x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}

So, the two solutions are

x_1 = \frac{-11+\sqrt{137}}{2}

x_2 = \frac{-11-\sqrt{137}}{2}

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irina [24]

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valentina_108 [34]

Answer:

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Step-by-step explanation:

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Hope this helps!

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Answer:

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Step-by-step explanation:

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