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3 years ago

Evaluate (find the output or y value of) the following function for x=5. y=3x2-8

Mathematics

1 answer:

Kobotan [32]3 years ago

3 0

The answer for y is y= -2

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Indicate in standard form the equation of the line passing through the given point and having the given slope

Naddik [55]

ANSWER

The equation is

$y - 5x + 20 = 0$

EXPLANATION

Let the equation be
$y = mx + c$

where
$m = 5$
is the slope of the line.

We substitute this value to obtain,

$y = 5x + c$

Since the line passes through
$(4,0)$
we can use this point to determine the value of c.

We substitute this point to obtain,

$0 = 5(4) + c$

$0 = 20 + c$

$c = - 20$

Our equation now becomes

$y = 5x - 20$

We can write this in standard form as

$y - 5x + 20 = 0$

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).

QveST [7]

Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

$\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}$

Using the section formula expressed as

$[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]$

In this case,

$\begin{gathered} m=1 \\ n=2 \end{gathered}$

where

$\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}$

Thus, by substitution, we have

$\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}$

Hence, the y-coordinate of the point P is

$0$

8 0

2 years ago