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dezoksy [38]
3 years ago
12

Write the expanded form of the expression. 6(3x - 7)

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
3 0
Firstly multiply 3x by 6 which gives you 18x
then multiply 6 and -7 which is -42. The final result is 18x-42.
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Musya8 [376]

Answer:

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3 years ago
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Points A, B, C, D, and O have coordinates (0, 3), (4, 4), (4, y), (4, 0), and (0, 0), respectively. The area of ACDO is 5 times
belka [17]

Solution:

Area of Quadrilateral ACDO= Area (ΔAOD)+Area(ΔACD)-----(1)

Area of Quadrilateral ABDO= Area (ΔAOD)+Area(ΔABD)------(2)

⇒ (1) = 5 ×(2)→→→→GIven

→Area (ΔAOD)+Area(ΔACD)=5 Area (ΔAOD)+5 Area(ΔABD),

→5 Area (ΔABD)+4 Area (ΔAOD)-Area (ΔACD)=0-----(3)

As, Area of a Triangle ={\text{having vertices}} (x_{1},y_{1}),(x_{2},y_{2}) {\text{and}} (x_{3},y_{3})=\frac{1}{2}\times[x_{1}(y_{2}-y_{3})-x_2(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})]

Area (ΔACD)

=\frac{1}{2}[0(y-0)-4(0-3)+4(3-y)]\\\\= \frac{1}{2}[12+12-4y]\\\\=12-2 y

Area (ΔABD)

=\frac{1}{2}[0(4-0)-4(0-3)+4(3-4)]\\\\ =\frac{1}{2}[12-4]=4

Area  (ΔAOD)=\frac{1}{2}[0(3-0)-0(0-0)+4(0-3)]=6

Putting these values in equation (3)

→20+24-12+2 y=0

→  2 y= -32

Dividing both sides by , 2 we get

→y= -16

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3 years ago
Lauren was late 36 days of the 180 days school year. What is the percent of the school year was Lauren late
iren2701 [21]

Step-by-step explanation:

percent = value when compare in 100

Lauren late = 36/180 × 100

.......

7 0
3 years ago
Use the Pythagorean theorem to find the missing side.
muminat
A2 + B2 = C2
A2 + 484 = 1024
A2 = 540
540 squared = 23.24
A = 23.24
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3 years ago
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Eddi Din [679]

Answer:

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3 years ago
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