Question

It is a geometric sequence where you have to find the ratio MILTIPLY ONLY and the sequence is 9,-3,1,-1/3

Answer 1

Answer:

The common ratio to the given geometric sequence is $-\frac{1}{3}$

Therefore common ratio is $r=-\frac{1}{3}$

Step-by-step explanation:

Given sequence is 9,-3,1,$-\frac{1}{3}$

Given that the given sequence is a geometric sequence

To find the common ratio of the given sequence :

Let $a_1=9,a_2=-3,a_3=1,a_4=-\frac{1}{3}$

Common ratio $r=\frac{a_2}{a_1}$

Substitute $a_1=9,a_2=-3$

$r=\frac{-3}{9}$

$=-\frac{1}{3}$

Therefore $r=-\frac{1}{3}$

Common ratio $r=\frac{a_3}{a_2}$

Substitute $a_3=1,a_2=-3$

$r=\frac{1}{-3}$

Therefore $r=-\frac{1}{3}$

The common ratio to the given geometric sequence is $-\frac{1}{3}$

Therefore common ratio is $r=-\frac{1}{3}$