<span>2x^2 + 3x + 5 = 0
a = 2 b = 3 and c = 5
x = [-b +-sq root(b^2 -4ac)] / 2a
</span><span>x = [-3 +-sq root(9 -4*2*5)] / 4
x = [-3 +-sq root(9 - 40)] / 4
</span><span>x = -(3 / 4) + sq root (-36) / 4
</span><span>x = -(3 / 4) - sq root (-36) / 4
</span>
Answer:2
Step-by-step explanation:
The slope (m) and the ordered pairs are given.
In order to arrive at the standard form : AX + BY = C, we need to form the slope-intercept form first : y = mx + b
Substitute the values in order to get the intercept (b)
y = mx + b
5 = 5/4 * 4 + b
5 = 5 + b
b = 0
So given the m = 5/4, b = 0
y = mx + b
y = 5/4x+ 0
Converting it to Standard Form
y = 5/4x + 0
5/4x - y = 0 (multiply both sides by 4)
5x - 4y = 0
<span>So the Standard form is 5x - 4y = 0</span>
