Solve for x: -2(x+3)= -2 - 6 0 3 all real numbers no solution

2 answers:

5 0

Distribute through the parentheses
Cancel equal terms on both sides of the equation Divide both sides of the equation by and it would be x=1

sleet_krkn [62]4 years ago

3 0

Answer:

Step-by-step explanation:

-2 is multiply by x and 3 then from left the number are replace in right then like term are simplify.

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Use the rational zeroes theorem to state all the possible zeroes of the following polynomial:

Mkey [24]

Answer:

All the possible zeroes of the polynomial: f(x) = $3x^{6} + 4x^{3} - 2x^{2} +4$ are ±1 , ±2 , ±4 , ± $\frac{1}{3}$ , ± $\frac{2}{3}$ , ± $\frac{4}{3}$ by using rational zeroes theorem.

Step-by-step explanation:

Rational zeroes theorem gives the possible roots of polynomial f(x) by taking ratio of p and q where p is a factor of constant term and q is a factor of the leading coefficient.

The polynomial f(x) = $3x^{6} + 4x^{3} - 2x^{2} +4$

Find all factors (p) of the constant term.

Here we are looking for the factors of 4, which are:

±1 , ±2 and ±4

Now find all factors (q) of the coefficient of the leading term

we are looking for the factors of 3, which are:

±1 and ±3

List all possible combinations of ± $\frac{p}{q}$ as the possible zeros of the polynomial.

Thus, we have ±1 , ±2 , ±4 , ± $\frac{1}{3}$ , ± $\frac{2}{3}$ , ± $\frac{4}{3}$ as the possible zeros of the polynomial

Simplify the list to remove and repeated elements.

All the possible zeroes of the polynomial: f(x) = $3x^{6} + 4x^{3} - 2x^{2} +4$ are ±1 , ±2 , ±4 , ± $\frac{1}{3}$ , ± $\frac{2}{3}$ , ± $\frac{4}{3}$

Learn more about Rational zeroes theorem here -https://brainly.ph/question/24649641

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7 0

2 years ago

6⁴ (8003 - 7987) + (20.3 - 1.32) = ?

astraxan [27]

Answer:

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