Given :
The diagonals of rhombus ABCD intersect at E.
∠CAD = 20°.
To Find :
The angle ∠CDA.
Solution :
We know, diagonals of a rhombus bisects each other perpendicularly.
So, ∠DEA = 90°.
In triangle ΔEAD :
∠EAD + ∠AED + ∠EDA = 180°
20° + 90° + ∠EDA = 180°
∠EDA = 70°
Now, we know diagonal of rhombus also bisect the angle between two sides .
So, ∠CDA = 2∠EDA
∠CDA = 2×70°
∠CDA =140°
Therefore, ∠CDA is 140°.
I think very well that it is A or B. With my experience, but you might want to keep doing research.
Answer:
it would the letter B
Step-by-step explanation:
the y intercept for function 1 is 3 and the y intercept for function 2 is 5
1m = 100cm
1cm → 0.5m
1cm → 0.5 · 100cm = 50cm
The scale: 
length = 26.8cm · 50 = 1,340cm = 13.40m
width = 12.2cm · 50 = 610cm = 6.10m
The area of the court:
A = 13.40 · 6.10 = 81.74 m²
The percent increase of 36;63 is 75 percent
