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MAXImum [283]
3 years ago
15

Choose the true statement. A) -2/3 < -3/4 B) -2/3 > -3/4 C) -2/3 = -3/4

Mathematics
2 answers:
raketka [301]3 years ago
7 0

Answer:

B) -2/3 > -3/4

Step-by-step explanation:

Both numbers are negative. Of two negative numbers, the closer one to zero on the number line is greater. -2/3 is closer to zero on the number line than -3/4, so -2/3 is greater than -3/4.

B) -2/3 > -3/4

Elenna [48]3 years ago
4 0
The answer is B because -2/3 is closer to 0, making it greater
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Is there a fast trick to convert centimeters to feet?
ElenaW [278]

Answer:

Step-by-step explanation:

The only way I know is to divide the centimeters by 30.48

4 0
2 years ago
What is the diameter of a circular field whose area is 616cm^2<br><br>​
Oksana_A [137]

Answer:

<h2>28cm</h2>

Step-by-step explanation:

d=2\sqrt{\frac{A}{\pi}} =2\sqrt{\frac{616}{\pi} }≈28.00563cm

rounding 28.00563 to 28.

So hence, your answer is 28cm

-------------------------------------------------------------------------------------------------------------The beautiful thing about learning is that no one can take it away from you!

B.B.King

Thanks!

Have a great day!

~ms115~

3 0
2 years ago
Read 2 more answers
Car A travels 6 miles in 8 minutes at a constant speed. if this car continues to travel at this rate, how many minutes would it
ivanzaharov [21]

Answer:

I'm guessing 12 not sure why just guessing

4 0
3 years ago
Find LCM of 9-p^2 and p^2+3p​
snow_lady [41]

Answer:

(3+p)

Step-by-step explanation:

solution

first expression=9-P^2

=3^2 - P^2

=(3+P) (3-p)

second expression=p^2 + 3p

= p(3+p)

Therefore lCM= (3+p)

3 0
3 years ago
The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(
forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

a)

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

b)

Considering that P(BIA)= \frac{P(AnB)}{P(A)} you can clear the intersection from the formula P(AnB)= P(B/A)*P(A) and apply it for the given events:

P(A_1nB)= P(B/A_1) * P(A_1)= 0.20*0.35= 0.07

P(A_2nB)= P(B/A_2)*P(A_2)= 0.05*0.50= 0.025

c)

The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:

P(B)= (A₁∩B) + P(A₂∩B)=  0.07 + 0.025= 0.095

d)

The Bayes' theorem states that:

P(Ai/B)= \frac{P(B/Ai)*P(A)}{P(B)}

Then:

P(A_1/B)= \frac{P(B/A_1)*P(A_1)}{P(B)}= \frac{0.20*0.35}{0.095}= 0.737 = 0.74

P(A_2/B)= \frac{P(B/A_2)*P(A_2)}{P(B)} = \frac{0.05*0.50}{0.095} = 0.26

I hope it helps!

5 0
3 years ago
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