Can someone answer this pls
2 answers:
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Answer:
Step-by-step explanation:
Given
--- Height
--- Width
---- Length
Solving (a): The lateral surface area (L)
This is calculated as:
This gives:
Solving (b): The total surface area (T)
This is calculated as:
This gives:
Answer:
B. x ≥ 3 or x ≤ −2
Step-by-step explanation:
<u>Inequalities</u>
Solve the inequality:
Subtracting 6:
Factoring:
(x-3)(x+2) ≥ 0
We have a product that must be greater or equal to 0. This can only happen if:
x - 3 ≥ 0 and x + 2 ≥ 0
Or:
x - 3 ≤ 0 and x + 2 ≤ 0
The first couple of conditions yields to:
x ≥ 3 and x ≥ -2
Which lead to the solution
x ≥ 3 [1]
The second couple of conditions yields to:
x ≤ 3 and x ≤ -2
Which lead to the solution
x ≤ -2 [2]
The final solution is [1] or [2]:
Answer:
B. x ≥ 3 or x ≤ −2
Answer:
Recursive: f(1) = 1; f(n) = f(n-1)/3
Equation: f(x) = 5/3·(1/3)^(x-1)
Step-by-step explanation:
You know this is an exponential function because sequential lines in the table have a common ratio of f(x) values:
f(2)/f(1) = (5/9)/(5/3) = 3/9 = 1/3
f(3)/f(2) = (5/27)/(5/9) = 9/27 = 1/3
and it continues like that.
Besides telling you the function is exponential, it also tells you that each term is 1/3 of the previous term.
<h3>Recursive formula</h3>The value of f(1) is read from the table. For x = 1, that value is ...
f(1) = 5/3
As we noticed above, each term is 1/3 the previous term, so the recursive relation is ...
f(n) = (1/3)·f(n-1)
<h3>Equation</h3>The general form of the equation for a geometric (exponential) relation is ...
f(x) = f(1)·r^(x-1) . . . . . . where f(1) is the first term, and r is the common ratio
For this function, we have f(1) = 5/3 and r = 1/3, so the equation is ...
f(x) = 5/3·(1/3)^(x-1)
__
<em>Additional comment</em>
When given values of x that count from 1, we often express the equation in terms of (x-1). That equation can be simplified so the exponent is x.
f(x) = 5·(1/3)^x
<h2>Answer:</h2><h3>b. n is odd</h3><h2>Step-by-step explanation:</h2>
In this problem, we assume that is a whole number. The definition of inverse functions tells us that a function
has an inverse function if and only if the function is one-to-one, that is, if there is no any horizontal line intersecting the graph of
at more than one point. This only happens if
is odd. This is called the Horizontal Line Test for Inverse Functions. So let's take two examples:
FIRST:
Since n is even, an horizontal line will pass through two points as indicated in the first figure below.
SECOND:
Since n is odd, an horizontal line will pass through just one point as indicated in the second figure below.