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Gemiola [76]
2 years ago
14

Please help. I will give ten points for answer

Mathematics
1 answer:
galina1969 [7]2 years ago
6 0

Answer: 2nd graph and the point is (6,7)

Step-by-step explanation:

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41,984 idk what the last line is for
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What is 51,988 rounded to the nearest ten thousand
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50,000 because if the number is lower than 5 than you round down and thing higher than 5 is rounded up
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Evaluate the expression.<br> 3–6–(2+6)2
Gekata [30.6K]

Answer:-19

Step-by-step explanation:

7 0
3 years ago
I need you to answer with a, b, c, d
solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

\begin{gathered} ax^2+bx+c=0 \\  \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}

For the given function:

f(x)=2x^2-10x-3x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}x=\frac{10\pm\sqrt[]{100+24}}{4}\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\  \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\  \end{gathered}\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\  \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\  \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Then, the zeros of the given quadratic function are:

\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\  \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Answer: Third option

8 0
1 year ago
50 points
Georgia [21]

(680 * d) - (960 * d) + 52000 =

is the equation, i’m not sure what the total answer is though.

Julianne will start making a profit on day 55 or 54. Check again, because it could be either.

Please mark brainliest , thank you , and have a great day .

7 0
3 years ago
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