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aniked [119]
3 years ago
5

58 less than the product of 75 and a number is 283.

Mathematics
1 answer:
Vadim26 [7]3 years ago
6 0
(75 * X) - 58 = 283

Not really much to explain here, sorry.
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Natalka [10]
<span>-9=2n
n = -9/2 = -4.5</span>
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Find the length of the hypotenuse round your answer to the nearest hundred
Ede4ka [16]
A. 7+4=11. That’s the answer to the hypotenuse.
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Solve 3 and get 70 pts
Lena [83]
The first one would be A, the lower quartile is given, because the 5 number summary has been given. The second one would be 99, because 97 gives 89.6 and 98 gives 89.8. And the third one would be there are exactly 3 students with 4 pairs of shoes. Hope this helps! If you need anything else let me know.
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Read 2 more answers
A microscope can magnify the object it is looking at 10×4 times. How many times is that? (MCC.8.EE.3) A. 40,000 times B. 40 time
damaskus [11]

Answer:

10×4 = 40

10^4 = 10,000

Step-by-step explanation:

10^4 is another way to write 10⁴ = 10·10·10·10 = 10,000.

Essentially, the exponent tells you how many places to the right of the leading digit the decimal point lies (here, the number of zeros in the number).

_____

<em>Comment on the answer choice</em>

The appropriate answer depends on what you mean by your problem statement. Some microscopes magnify 40 times; others magnify 10,000 times, so we cannot tell the appropriate answer using our knowledge of microscopes.

3 0
3 years ago
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Anna007 [38]

h(-3) - h( - 2) = -  \frac{5}{  8} \\ \\

Step-by-step explanation:

\boxed{h(x) =  \frac{2 {x}^{2}  - x + 1}{3x - 2}}

h(2) =  \frac{2 {(2)}^{2}  - (2) + 1}{3(2) - 2}

h(2) =  \frac{2 {(4)}  - 2 + 1}{6 - 2}

h(2) =  \frac{ 8  - 1}{4}

h(2) =  \frac{7}{4}

h( - 3) =  \frac{2 {( - 3)}^{2}  - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) =  \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) =  \frac{18 + 4}{ - 11} \\ h( - 3) =    \frac{22}{  - 11} \\ h(-3) = -2

h( - 2) =  \frac{2 {( - 2)}^{2}  - ( - 2) + 1}{3( - 2) - 2} \\ h( - 2) =  \frac{2 (4)  +  2+ 1}{- 6 - 2} \\ h( - 2) =  \frac{8 +  3}{- 8} \\ h( - 2) =  \frac{11}{- 8}

h(3) - h( - 2) = -2 - \frac{11}{- 8} \\ h(3) - h( - 2) =-2 + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-2}{1}+ \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16}{8} + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16+11}{8} \\ h(3) - h( - 2) = \frac{-5}{8} \\ - \frac{5}{ 8}

5 0
3 years ago
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