The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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9x - 24 + 4x = -24 + 14x - x
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0 = 0
Answer is All real numbers
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Complete question: The graph of f(x)= power of 3√x + 8 is shown.
Step-by-step explanation:
See attachment for the missing graph.
when x = -16 ; y = -2
when x = -12 ; y = -1.5
when x = -8 ; y = 0
when x = -6 ; y = 1.25
when x = 0 ; y = 2
when x = 6 ; y = 2.5
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Answer: A B
legs~ The two congruent sides of an isosceles triangle that has only two congruent sides.
base ~The noncongruent side of an isosceles triangle that has only two congruent sides.
Step-by-step explanation:
