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lord [1]
3 years ago
14

The area of a rectangular flower bed is 24 square feet. The perimeter of the same flower bed is 22 feet. What are the dimensions

of the flower bed?
A. 2 ft by 12 ft
B. 3 ft by 8 ft
C. 3 ft by 6 ft
D. 4 ft by 6 ft
Mathematics
1 answer:
Vesna [10]3 years ago
4 0

Answer:

3 ft by 8 ft

Step-by-step explanation:

We were given the area as 24 square feet which means that

L×w= 24....eqn(1)

We were given the perimeter as 22 square feet which means that

22= 2(L +w).......eqn(2)

If we divide both cause by 2 in eqn(2) we have

11= L+ w .....eqn(3)

W= 11-L.........eqn(4)

Substitute eqn(4 into eqn(1)

L× (11-L)=24

-L^2 +11L-24=0

If we factorize

(L-8)(L-3)

L=3 or 8

From eqn4)

W=11-L

At L=3

W=11-3=8

Hence, the dimension is 3 ft by 8 ft

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Cost = 616000 DHS per square centimetre.

Step-by-step explanation:

curved surface of a cylinder = 2\pirh

r = 7 cm

h = 1400 m = 140000 cm

The outer curved surface area of the cylinder = inner curved surface area of the cylinder

The inner curved surface of the cylinder = 2\pirh

                                      = 2 x \frac{22}{7} x 7 x 140000

                                      = 2 x 22 x 1 x 140000

                                      = 6160000

The inner curved surface of the cylinder is 6160000 square centimetre.

But, the cost of painting is at the rate of 10 DHS per square centimetre.

The inner curved surface of the cylinder = 6.16 x 10^{6} square centimetre.

cost of painting the inner curved surface area = \frac{6.16*10^{6} }{10}

                                                                       = 616000 DHS per square centimetre

The cost of painting the inner surface is 616000 DHS per square centimetre.

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2 years ago
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