Original coordinates of the points:
A (8,15) ; B (12,13) ; C (8,10)
Dilated scale factor of 3.
A ⇒ 3x = 3(8) = 24 ; 3y = 3(15) = 45 ⇒ A' (24,45)
B ⇒ 3x = 3(12) = 36 ; 3y = 3(13) = 39 ⇒ B' (36, 39)
C ⇒ 3x = 3(8) = 24 ; 3y = 3(10) = 30 ⇒ C' (24, 30)
The given image forms a right triangle. So, I'll get the short leg and long leg of the right triangle to solve for the hypotenuse, length of CB.
Short leg: y value of B and C
39 - 30 = 9
Long leg: x value of B and C
36 - 24 = 12
a² + b² = c²
9² + 12² = c²
81 + 144 = c²
225 = c²
√225 = √c²
15 = c
The length of CB is 15 units.
2x + 3
2x + 3
2x * 2x = 2x^2
2x * 3 = 6x
2x * 3 = 6x
3 * 3 = 9
Add them all up
2x^2 + 12x + 9
Answer:
4x+11m
Step-by-step explanation:
3x+x+5m+6m=4x+11m
Answer:
5x + 4x = 20
Step-by-step explanation:
You have your x and y values and if you substitute them in you find yourself with 40 - 20 = 24 this doesn't make sense. So you get another answer which can be set to 20 and 40 - 20 = 20 therefore you you can make sure that your line intersects with your x and y values.
The answer is:
________________
n = ¼ ; or, write as:
n = 0.25
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Explanation:
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-7 / (2n) = 49 ;
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-49 * (2n) = -7 ;
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Divide each side by "(-49)" ; to isolate the "2n" on one side, and to get rid of the "negative" values:
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[-49*(2n)] / -49 = -7/ -49 ; to get:
_______________________________
2n = (½); Now, divide EACH side of the equation by "2"; to isolation "n" on one side of the equation, and to solve for: "n";
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2n / 2 = (½) / 2 ;
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To get:
_______________
n = ¼ ; or, write as:
n = 0.25
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