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Svetradugi [14.3K]
3 years ago
12

$50.00+40.00 50.00-40.00​

Mathematics
1 answer:
V125BC [204]3 years ago
4 0

Answer:

50.00 + 40.00

es 90.00

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Point M is the midpoint of segment QR. If QM = 16 + x and MR = 2(x + 2), find the length of QM.
pav-90 [236]
Just add them
QM+MR=QR
16+x+2(x+2)=QR
16+x+2x+4=QR
20+3x=QR
6 0
3 years ago
Mathematics Areas and perimeters ​
sweet-ann [11.9K]

Answer:

54.5 Sq. cm

Step-by-step explanation:

<em>area of a right angled triangle = 1/ 2 × base × height </em>

(here, the base is 8 and height is 6)

= 1/ 2 × 6 × 8

= 4 × 6

<u>= 24 Sq. cm</u>

<em>area of a circle</em> = \pi r²

(r is the radius that is diameter/ 2, and the value of \pi is 3. 14)

  • r = 10/ 2 = 5 cm

= 3. 14.× (5)²

= 3.14 × 25

<u>= 78.5 Sq. cm</u>

area of the shaded region = area of Circle - area of triangle

= 78.5 - 24

<h3>= 54.5 Sq. cm</h3>

that is option 3

7 0
3 years ago
What is the equation of the line that passes through the point (5,-2)and has a slope of the fraction 6/5?
Tju [1.3M]

Answer:

6x-5y-40 = 0

Step-by-step explanation:

y-(-2)=6/5(x-5)

5(y+2)= 6(x-5)

5y+10 =6x-30

6x-5y-40 = 0

6x-5y-40 = 0 is the answer

5 0
3 years ago
Can someone please help me with this problem.
iren [92.7K]
X^2 + 3x - 6

This is because x^2 and 3x have nothing they can combine with, leaving them as their own number. 1 + - 6 will give you -5 as adding to a negative only reduces not adds entirely.

Hope this helps!
8 0
3 years ago
If fence poists are to be placed in a row 7 feet apart, how many posts are needed for 210 feet of fence?
ollegr [7]

Answer:

31

Step-by-step explanation:

210 ft ÷ 7 ft = 30

There are 30 7-ft lengths of fence.

Think of putting a post at the end of each 7-ft length. That means you need 30 posts. Now you must add 1 post for the beginning.

Answer: 31

8 0
2 years ago
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