Is 1 hour is 9 miles, how many hours is 15 miles?<br><br> 1 hr = 9 mi<br><br> _

To show this number using scientific notation, you will look at where the decimal point is and imagine that in the original number. Then count the number of place values to the right of this. That will be the exponent that belongs with the 10 because that is how many place values (groups of 10s) the number has past the decimal point.

The answer is 3.31 x 10^26 light years. ^ means to the power of.

6 0

3 years ago

Read 2 more answers

Sal made 8 ft of sausage links on Friday morning. He used 4 ft for dinner service on Friday night. On Saturday morning, he made

oee [108]

Answer:

Net change in the amount of sausage Sal had from Friday morning until after dinner service Saturday night = 8 - 0 = 8 ft

Step-by-step explanation:

Amount of sausage links made on Friday morning = 8 ft

Amount of sausage links used on Friday night = 4 ft

Amount of sausage links remaining = 8 - 4 = 4ft (i)

Amount of sausage links made on Saturday morning = 8 ft (ii)

So,

Total amount of sausage links = 8 + 4 = 12 ft (from (i) and (ii) )

Amount of sausage links used on Saturday night = 12 ft

Amount of sausage links remaining = 12 - 12 = 0 ft

Net change in the amount of sausage Sal had from Friday morning until after dinner service Saturday night = 8 - 0 = 8 ft

8 0

3 years ago

The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand

Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 18.6, \sigma = 5.9$

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{21 - 18.6}{5.4}$

$Z = 0.44$

$Z = 0.44$ has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have $n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768$