Answer:
Top 3%: 4.934 cm
Bottom 3%: 4.746 cm
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 4.84, \sigma = 0.05](https://tex.z-dn.net/?f=%5Cmu%20%3D%204.84%2C%20%5Csigma%20%3D%200.05)
Top 3%
Value of Z when Z has a pvalue of 1 - 0.03 = 0.97. So X when Z = 1.88.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![1.88 = \frac{X - 4.84}{0.05}](https://tex.z-dn.net/?f=1.88%20%3D%20%5Cfrac%7BX%20-%204.84%7D%7B0.05%7D)
![X - 4.84 = 0.05*1.88](https://tex.z-dn.net/?f=X%20-%204.84%20%3D%200.05%2A1.88)
![X = 4.934](https://tex.z-dn.net/?f=X%20%3D%204.934)
Bottom 3%
Value of Z when Z has a pvalue of 0.03. So X when Z = -1.88.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![-1.88 = \frac{X - 4.84}{0.05}](https://tex.z-dn.net/?f=-1.88%20%3D%20%5Cfrac%7BX%20-%204.84%7D%7B0.05%7D)
![X - 4.84 = 0.05*(-1.88)](https://tex.z-dn.net/?f=X%20-%204.84%20%3D%200.05%2A%28-1.88%29)
![X = 4.746](https://tex.z-dn.net/?f=X%20%3D%204.746)
Answer:
Step-by-step explanation:
<u>We know that:</u>
- -4 + x = 16 [x = difference between two temperatures]
<u>Solution:</u>
- -4 + x = 16
- => x = 16 + 4
- => x = 20
Hence, the difference between the two temperatures is 20°.
Answer:
3x^5 - 4x^4 - 5x^3 + x^2 + 11x - 6
The null hypothesis to test the claim that the proportion of people who owns cats is larger than 60% of the significance level is
:μ<0.06.
Given that the significance level is 0.10.
We are required to form the null hypothesis to test the claim that the proportion of people who owns cats is larger than 60% the significance level.
Hypothesis is a statement which is tested for its validity. Null hypothesis is the statement which is accepted or not by z test,t test,f test ,chi-square test or any other test.
We have to take opposite of the statement to form a null hypothesis. Since we have to check whether the proportion of people who owns cats is larger than 60% of the significance level, we have to assume that it is smaller than 60% of the significance level.
60% of the significance level=0.60*0.10=0.06.
Null hypothesis is
:μ<0.06
Hence the null hypothesis to test the claim that the proportion of people who owns cats is larger than 60% of the significance level is
:μ<0.06.
Question is incomplete.The question should include the following:
Find the null hypothesis for the testing.
Learn more about hypothesis at brainly.com/question/11555274
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Answer:
3.67
Step-by-step explanation:
the equation is 3x + 5= 16
do 16 - 5 to get 11
next do 11 divided by 3 to get 3.67
hope this helps :)
this answer may be incorrect because the answer was really 3.66666666667