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3 years ago

Find an equation for the line through (-7,7) and parallel to y=2x-3

Mathematics

1 answer:

kaheart [24]3 years ago

4 0

The answer would be B because a line is a parallel as long as the mx remains the same

Hope this helped.

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What is the Value of x

Ugo [173]

Answer:

x = 11

Step-by-step explanation:

A segment parallel to a side of a triangle cuts off proportional segments on the sides.

48/6 = (3x + 7)/5

8 = (3x + 7)/5

3x + 7 = 40

3x = 33

x = 11

8 0

2 years ago

Billy joined Franco's today. His membership cost him $50. He has to pay $2 each time he goes.

Darina [25.2K]

Answer:

Step-by-step explanation:

M is the membership and b is billy

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3 years ago

A right circular cylinder has a height of 5in. And a base area of 20 in2. What is the volume of the cylinder

koban [17]

Answer:

V=100in³

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find a and b so that f(x) = x^3 + ax^2 + b will have a critical point at (2,3).

Digiron [165]

Using the critical point concept, it is found that a = -3 and b = 7.

<h3>What are the critical points of a function?</h3>

The critical points of a function are the values of x for which:

$f^{\prime}(x) = 0$

In this problem, the function is:

$f(x) = x^3 + ax^2 + b$

Hence, the derivative is:

$f^{\prime}(x) = 3x^2 + 2ax$

Then:

$f^{\prime}(x) = 0$

$3x^2 + 2ax = 0$

$x(3x + 2a) = 0$

$x = 0$

$3x + 2a = 0$

$3x = -2a$

$x = -\frac{2a}{3}$

Since the critical point is at x = 2, we have that:

$-\frac{2a}{3} = 2$

$-2a = 6$

$2a = -6$

$a = -3$

Then:

$f(x) = x^3 - 3x^2 + b$

Critical point at (2,3) means that when $x = 2, y = 3$ , then:

$3 = 2^3 - 3(2)^2 + b$

$8 - 12 + b = 3$

$b = 7$

You can learn more about the critical point concept at brainly.com/question/2256078

4 0

1 year ago

At a reunion 14 5/8 blueberry pies were eaten. Write the amount of pies as a decimal .

alekssr [168]

Answer:

14.625

Step-by-step explanation:

8 0

3 years ago