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3 years ago

Blake rolls a number cube ten times and it lands on the number 5 three times.

Mathematics

1 answer:

icang [17]3 years ago

3 0

Answer:

Do more rolls of the number cube.

Step-by-step explanation:

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A standard six-sided die is rolled. what is the probability of rolling a number equal to 3? express your answer as a simplified

alexandr402 [8]

there is 1 number 3 on a 6 sided die

so the probability or rolling a 3 is 1/6

4 0

3 years ago

HELP PLEASEE no links hellpp

bezimeni [28]

Answer:

B and E

Step-by-step explanation:

perpendicular sides mean they will equal 90 degrees... so all rectangles and squares are perpendicular- a 90 degree triangle also is perpendicular. The Equatorial and the Acute triangle do not have 90 degree angles

4 0

3 years ago

Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ab

zhenek [66]

Answer:

test statistic is ≈ -0.36

p-value is ≈ 0.64

There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.

Step-by-step explanation:

a hypothesis test where H_0: mu = 235 and H_1:mu > 235

test statistic can be calculated as follows:

z= $\frac{X-M}{\frac{s}{\sqrt{N} } }$ where

sample mean driving distance (233.8 yards)

M is the average expected distance that the average golfer can hit the ball under null hypothesis. (235 yards)

s is the standard deviation (46.6 yards)

N is the sample size (192)

Then test statistic is z= $\frac{233.8-235}{\frac{46.6}{\sqrt{192} } }$ =-0.3568

p-value is 0.64 >0.05

There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.

6 0

3 years ago

A school has 1800 students 55 %of the students of girls. how many boys are in the school?

Katena32 [7]

Answer:

810 boys

Step-by-step explanation:

1800 students and 55% are girls.

100%-55%=45%

1800*0.45 = 810

1800*0.55 = 990

So there are 990 girls and 810 boys.

Hope this helps :)

3 0

2 years ago

Find an explicit solution to the Bernoulli equation. y'-1/3 y = 1/3 xe^xln(x)y^-2

NNADVOKAT [17]

$y'-\dfrac13y=\dfrac13xe^x\ln x\,y^{-2}$

Divide both sides by $\dfrac13y^{-2}(x)$ :

$3y^2y'-y^3=xe^x\ln x$

Substitute $v(x)=y(x)^3$ , so that $v'(x)=3y(x)^2y'(x)$ .

$v'-v=xe^x\ln x$

Multiply both sides by $e^{-x}$ :

$e^{-x}v'-e^{-x}v=x\ln x$

The left side can be condensed into the derivative of a product.

$(e^{-x}v)'=x\ln x$

Integrate both sides to get

$e^{-x}v=\dfrac12x^2\ln x-\dfrac14x^2+C$

Solve for $v(x)$ :

$v=\dfrac12x^2e^x\ln x-\dfrac14x^2e^x+Ce^x$

Solve for $y(x)$ :

$y^3=\dfrac12x^2e^x\ln x-\dfrac14x^2e^x+Ce^x$

$\implies\boxed{y(x)=\sqrt[3]{\dfrac14x^2e^x(2\ln x-1)+Ce^x}}$

4 0

3 years ago