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dsp73
3 years ago
15

I NEED HELP ! I WILL CASH APP YOU !

Mathematics
1 answer:
Amanda [17]3 years ago
3 0

Answer:B and D

Step-by-step explanation:big brain

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anastassius [24]
2x-4y=14
X=2y-2

2x-4y=14
x-2y=-2

x-2y=12
x-y=-6
5 0
2 years ago
A 1000 KG car has 50,000 joules of kinetic energy. What is the speed?
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Translate this sentence into an equation. The sum of 16 and Delia's height is 74. Use the variable d to represent Delia's height
Sedbober [7]
The answer is :

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2 years ago
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Given that cos θ = –12∕13 and θ is in quadrant III, find csc θ.
Trava [24]

Answer:

A

Step-by-step explanation:

We are given:

\displaystyle \cos(\theta)=-\frac{12}{13},\,\theta\in\text{QIII}

Since cosine is the ratio of the adjacent side over the hypotenuse, this means that the opposite side is (we can ignore negatives for now):

o=\sqrt{13^2-12^2}=\sqrt{25}=5

So, the opposite side is 5, the adjacent side is 12, and the hypotenuse is 13.

And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.

Cosecant is given by the hypotenuse over the opposite side. Thus:

\displaystyle \csc(\theta)=\frac{13}{5}

Since θ is in QIII, cosecant must be negative:

\displaystyle \csc(\theta)=-\frac{13}{5}

Our answer is A.

7 0
2 years ago
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Alex777 [14]
Average time on task 1 = \frac{3.4+4.1+6.5+8.1}{4}=5.5 seconds
Average time on task 2 = \frac{3.5+4.3+6.8+8.3}{4}=5.7 seconds
Average time on task 3 = \frac{4.3+4.1+6.5+7.9}{4}=5.7 seconds
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Average time on task 5 = \frac{3.6+4.2+6.7+8.1}{4}=5.65 seconds
4 0
3 years ago
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